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Kipish [7]
4 years ago
13

What is the length of the shadow cast on the vertical screen by your 10.0 cm hand if it is held at an angle of θ=30.0∘ above hor

izontal? Express your answer in centimeters to three significant figures. View Available Hint(s)
Physics
1 answer:
Alchen [17]4 years ago
5 0

Answer:

The  length is  D  =  5 \ cm

Explanation:

From the question we are told  that

     The  length of the  hand is  l  =  10.0 \ cm

      The  angle at the hand is  held is  \theta  =  30 ^o

Generally resolving the length the length of the hand to it vertical component we obtain that the length of the shadow on the vertical wall is mathematically evaluated as

             D  =  l * sin(\theta )

substituting values

             D  =  10 * sin (30)

             D  =  5 \ cm

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The equivalent resistance is D) 7.55 \Omega

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The equivalent resistance of n resistors in parallel is given by the equation:

\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}+...+\frac{1}{R_n}

For three resistors such as in this problem, the equation becomes

\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}

where we have the following:

R_1 = 10 \Omega is the resistance of the 1st resistor

R_2 = 50 \Omega is the resistance of the 2nd resistor

R_3 = 80 \Omega is the resistance of the 3rd resistor

Substituting, we find the equivalent resistance:

\frac{1}{R}=\frac{1}{10}+\frac{1}{50}+\frac{1}{80}=0.133 \Omega^{-1}

R=\frac{1}{0.133}=7.55 \Omega

Learn more about resistance:

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