4. Intermediate conductivity and a low melting point.
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Answer:
1.66 kg
Explanation:
Given that a 0.83-kg block is hung from and stretches a spring that is attached to the ceiling.
From Hook's law
F = Ke
But F = mg
Substitute mg for force in the Hook's law
Mg = ke
0.83 × 9.8 = ke
Make K the subject of formula
8.134 = Ke
K = 8.134 /e
Given that a second block is attached to the first one, and the amount that the spring stretches from its unstretched length triples.
That is
(0.83 + M) × 9.8 = K (3e)
Substitutes K into the above equation
(0.83 + M) × 9.8 = 8.134 / e (3e)
The e will cancel out
(0.83 + M) × 9.8 = 24.402
0.83 + M = 24.402/9.8
0.83 + M = 2.49
M = 2.49 - 0.83
M = 1.66 kg
Therefore, the mass of the second block is 1.66kg
Answer:
0.14
Explanation:
Flow rate is the volume flowing through a point at a particular time, in calcuing flow rate we have
Q= v*t
it in terms of Area, we have Q= A*v
Where A= area
v= velocity.
Solving the question , flow rate is constant then
A*v= constant
A(i) v(i)= A(f) v(f)
Where A(i)= initial area= 1.00cm^2
A(f)= final area= 0.400cm^2
V(i) and V(f) are the initial and final velocity respectively and the ratio of the two will gives us the factor
Substitute the values into the equation we have
1 V(i)= 4 V(f)
But we were told that the cross sectional area of 1.00cm^2 branches into 18 smaller arteries.
Then
1 V(i)=0.4 V(f)*(18)
1 V(i)=7.2V(f)
Then if we find the ratio of the velocity, we will get the factor.
V(f)/V(i)= 1/7.2
V(f)/V(i)=0.14
Hence, the factor of the average velocity of the blood reduced when it passes into these branches is 0.14
Equilibrium is the answer because they are reaching an equal temperature
