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Nat2105 [25]
3 years ago
12

If you have 5.22*1022 molecules of glucose (C6H12O6) how many grams is this?

Chemistry
1 answer:
lianna [129]3 years ago
7 0

Answer:

5.22*1022 molecules of glucose (C6H12O6)  is equal to 15.08 grams

Explanation:

Number of molecule of glucose in one mole = 6.023 * 10^{23}

Now mass of one mole of glucose = 180 grams

Number of moles in 6.023 * 10^{23} molecules of glucose = 1

Number of moles in 1 molecules of glucose =  \frac{1}{6.023 * 10^{23}}

Number of moles in 5.22 * 10^{22} molecules of glucose =  \frac{5.22* 10^{22}}{6.023 * 10^{23}}  = 0.083 moles

Weight of 0.083 moles

= 0.083 * 180\\= 15.08grams

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Vladimir79 [104]

Answers:

1. 3-ethyl-3-methylheptane; 2. 2,2,3,3-tetramethylpentane; 3. hexa-2,4-diene.

Explanation:

<em>Structure 1 </em>

  1. Identify and name the longest continuous chain of carbon atoms (the main chain has 7 C; ∴ base name = heptane).
  2. Identify and name all the substituents [a 1C substituent (methyl) and a 2C substituent (methyl).
  3. Number the main chain from the end closest to a substituent.
  4. Identify the substituents by the number of the C atom on the main chain. Use hyphens between letters and numbers (3-methyl, 3-ethyl).
  5. Put the names of the substituents in alphabetical order in front of the base name with no spaces (3-ethyl-3-methylheptane)

<em>Structure 2</em>

  1. 5C. Base name = pentane
  2. Four methyl groups.
  3. Number from the left-hand end.
  4. If there is more than one substituent of the same type, identify each substituent by its locating number and use a multiplying prefix to show the number of each substituent. Use commas between numbers (2,2,3,3-tetramethyl).
  5. The name is 2,2,3,3-tetramethylpentane.

<em>Structure 3 </em>

  1. Identify and name the longest continuous chain of carbon atoms that passes through as many double bonds as possible. Drop the <em>-ne</em> ending of the alkane to get the root name <em>hexa-</em>.
  2. (No substituents).
  3. Number the main chain from the end closest to a double bond.
  4. If there is more than one double bond use a multiplying prefix to indicate the number of double bonds (two double bonds = diene) and use the smaller of the two numbers of the C=C atoms as the double bond locators (2,4-diene)
  5. Put the functional group name at the end of the root name (hexa-2,4-diene).

<em>Note</em>: The name 2,4-hexadiene is <em>acceptable</em>, but the <em>Preferred IUPAC Name</em> puts the locating numbers as close as possible in front of the groups they locate.

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Antibiotics are a type of medicine that kills bacteria. Antibiotics can be used to fight bacterial infections. Which of the foll
AysviL [449]

Answer:

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Explanation:

antibiotics can treat bacterial infections, such as:

   Most sinus infections.

   Strep throat.

   Urinary tract infections.

   Pneumonia.

   Most ear infections (otitis media)

   Nasty bacterial skin infections (impetigo)

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The proteins of all living things require<br> geometry of amino acids.
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8 0
3 years ago
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What powers explosions and fire?
docker41 [41]

Answer:

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4 0
3 years ago
Ydrogen and fluorine combine according to the equation h2(g) + f2(g) → 2 hf(g) if 5.00 g of hydrogen gas are combined with 38.0
Alexxx [7]
<span> Molar mass (H2)=2*1.0=2.0 g/mol
Molar mass (F2)=2*19.0=38.0 g/mol
Molar mass (HF)=1.0+19.0=20.0 g/mol

5.00 g H2 * 1mol H2 /2 g H2=2.50 mol H2 
38.0 g F2*1mol F2/38.0 g F2=1.00 mol F2

                                   H2(g) + F2(g) → 2 HF(g)
From reaction        1 mol      1 mol
From problem      2.50 mol   1 .00mol

We can see that  excess of H2, and that F2 is a limiting reactant.
So, the amount of HF is limited by the amount of F2.

</span>                                 H2(g) + F2(g) → 2 HF(g)
From reaction                      1 mol       2  mol
From problem                      1.00 mol  2.00mol

2.00 mol HF can be formed.

2.00 mol HF*20.0g HF/1mol HF=40.0 g HF can be formed
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3 years ago
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