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Zigmanuir [339]
3 years ago
5

A spring with k = 11 N/m is stretched 0.25 m. What force does the spring apply?

Physics
1 answer:
Fofino [41]3 years ago
5 0

Answer:

Potential

Explanation: Because it's being stretched, potential energy stores up in the spring. If the spring is released, then it has Kinetic.

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Using the Equation:
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where,
v = final velocity 
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<span><span>We know that vi = 0 because the ball was at rest initially.
</span><span>
Therefore,

Solving Eq.1 for acceleration,
 
</span></span> v² = vi² + 2 · a · s
 v² = 0 + 2 · a · s
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Rearranging for a,
a = v ²/2·<span>s
Substituting the values,
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<span>Now applying Newton's 2nd law of motion,
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<span>F = ma
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F = 153.4 N</span>
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