If you know the real modulus of the cable (Y), the length, and the area (based on the radius), you can compute the spring constant, k = AE/L. Then, if you know the force used, you can compute the displacement, using F = kd, or d = F / k = FL/(AE). Our answer should work out to units of length. So,
d = 803 N * 9.06 m / [pi*(0.574 cm)^2 * 2.0 x 10^11 N/m^2]
d = 3.5 x 10^-8 Nm^3 / (cm^2 * N)
d = 3.5 x 10^-8 m^3 / cm^2 * (100 cm / 1 m)^2
d = 3.5 x 10^-4 m
The formula for accelerational displacement is at^2/2, so we know that 3.9t^2/2 = 200, or 3.9t^2 = 400. t =

, at = v, so
This question involves the concepts of general gas equation and pressure.
The force exerted by the gas on one of the walls of the container is "74.08 KN".
First, we will use the general gas equation to find out the pressure of the gas:

where,
P = Pressure of the gas = ?
V = Volume of cube = (side length)³ = (10 cm)³ = (0.1 m)³ = 0.001 m³
n = no. of moles = 3 (since molecules equal to avogadro's number make up 1 mole)
R = general gas constant = 8.314 J/mol.K
T = Absolute Temperature = 24°C + 273 = 297 K
Therefore,

P = 7407.78 KPa
Now, the force on one wall can be given as follows:

where,
A = area of one wall = (side length)² = (0.1 m)² = 0.01 m²
Therefore,

<u>F = 74.08 KN</u>
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Learn more about the general gas equation here:
brainly.com/question/24645007?referrer=searchResults
Answer is given below
Explanation:
given data
pressure = double
volume = constant
solution
As we know that an Average velocity and rms velocity is directly proportional to square root of PV ..................1
so if we take P is doubled while keeping V constant
than Velocity increases by a factor
so that Factor = 1.414 for both the cases