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Ratling [72]
3 years ago
10

Our eyes can see light with an angular resolution of about 1’—equivalent to about a third of a millimeter at arm’s length. Suppo

se our eyes detected only infrared radiation, with 1° angular resolution. Would we be able to make our way around on Earth’s surface? To read? To sculpt? To create technology?
Physics
1 answer:
olya-2409 [2.1K]3 years ago
7 0

Answer:

We would not be able to make our way around the earth's surface, to read, to sculpt or to create technology because we cannot see!

Explanation:

The minimum angular separation that can be distinguished by an eye gives the angular resolution of the eye.

Given that the Angular resolution with infrared radiation is = 1.0^0 equal to 60'

This resolution is very much greater than that of the eye (1')

The angular resolution that our eyes can see is about  \frac{1}{3}mm  at arms length

Angular resolution of infrared = \frac{1}{3} * 60 = 20mm  at arms length

We therefore cannot read, sculpt or create technology because we cannot see.

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Anna11 [10]
If you know the real modulus of the cable (Y), the length, and the area (based on the radius), you can compute the spring constant, k = AE/L. Then, if you know the force used, you can compute the displacement, using F = kd, or d = F / k = FL/(AE). Our answer should work out to units of length. So, 
d = 803 N * 9.06 m / [pi*(0.574 cm)^2 * 2.0 x 10^11 N/m^2] 
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4 0
3 years ago
A race car starting from rest accelerates uniformly at a rate of 3.90 m/s^2 what is the cars speed after it has traveled 200 m.
snow_tiger [21]
The formula for accelerational displacement is at^2/2, so we know that 3.9t^2/2 = 200, or 3.9t^2 = 400. t = \sqrt{400/3.9} \approx 10.12739367, at = v, so 3.9 * 10.12739367 \approx 39.5  m/s
6 0
3 years ago
Read 2 more answers
A sealed cubical container 10.0 cm on a side contains three times Avogadro's number of molecules at a temperature of 24.0°C. Fin
rodikova [14]

This question involves the concepts of general gas equation and pressure.

The force exerted by the gas on one of the walls of the container is "74.08 KN".

First, we will use the general gas equation to find out the pressure of the gas:

PV = nRT

where,

P = Pressure of the gas = ?

V = Volume of cube = (side length)³ = (10 cm)³ = (0.1 m)³ = 0.001 m³

n = no. of moles = 3 (since molecules equal to avogadro's number make up 1 mole)

R = general gas constant = 8.314 J/mol.K

T = Absolute Temperature = 24°C + 273 = 297 K

Therefore,

P = \frac{(3)(8.314\ J/mol.k)(297\ K)}{0.001\ m^3}

P = 7407.78 KPa

Now, the force on one wall can be given as follows:

P =\frac{F}{A}\\\\F=PA

where,

A = area of one wall = (side length)² = (0.1 m)² = 0.01 m²

Therefore,

F=(7407.78\ KPa)(0.01\ m^2)\\

<u>F = 74.08 KN</u>

<u></u>

Learn more about the general gas equation here:

brainly.com/question/24645007?referrer=searchResults

5 0
3 years ago
I'll give 20 points!!!
qwelly [4]

Answer:

Its b)

Explanation:

4 0
3 years ago
If the pressure in a gas is doubled while its volume is held constant, by what factor do vrms change
Nat2105 [25]

Answer is given below

Explanation:

given data

pressure = double

volume = constant

solution

As we know that an Average velocity and rms velocity is directly proportional to square root of PV ..................1

so if we take P is doubled while keeping V constant

than Velocity increases by a factor \sqrt{2}  

so that Factor = 1.414 for both the cases

8 0
3 years ago
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