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Ratling [72]
3 years ago
10

Our eyes can see light with an angular resolution of about 1’—equivalent to about a third of a millimeter at arm’s length. Suppo

se our eyes detected only infrared radiation, with 1° angular resolution. Would we be able to make our way around on Earth’s surface? To read? To sculpt? To create technology?
Physics
1 answer:
olya-2409 [2.1K]3 years ago
7 0

Answer:

We would not be able to make our way around the earth's surface, to read, to sculpt or to create technology because we cannot see!

Explanation:

The minimum angular separation that can be distinguished by an eye gives the angular resolution of the eye.

Given that the Angular resolution with infrared radiation is = 1.0^0 equal to 60'

This resolution is very much greater than that of the eye (1')

The angular resolution that our eyes can see is about  \frac{1}{3}mm  at arms length

Angular resolution of infrared = \frac{1}{3} * 60 = 20mm  at arms length

We therefore cannot read, sculpt or create technology because we cannot see.

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If a car accelerated from 5 m/s to 25 m/s in 10 seconds what is it's acceleration?
Alex_Xolod [135]

Answer:

a= (25-5) /10=2m/s^2

............

6 0
3 years ago
If 500g of water at 20 degrees C is mixed with 750g of water at 30 degrees C, what will the temperature of the mixture be?
hjlf

Answer:

26 ^\circ C

Explanation:

Given that the temperature of  500g of water and 750 g of water are

at 20^{\circ}C and 30^\circ C respectively.

Let m_1=500g, T_1= 20^\circ C

and m_2=750g, T_2= 30^\circC.

The specific heat capacity of water is,

C= 4.186 J/g ^\circ C.

Let the final temperature of the mixture be T^\circ C.

As there is no energy loss, so, the energy loss by the water at higher temperature, i.e. 30^\circ C, will be equal to the energy gain by the water at lower temperature, i.e. 20^{\circ}C.

m_2C (T_2-T)=m_1C(T-T_1)

\Rightarrow m_2 (T_2-T)=m_1(T-T_1) [ both sides divided by C ]

\Rightarrow m_2T_2-m_2T=m_1T-m_1T_1

\Rightarrow m_1T+m_2T=m_1T_1+m_2T_2

\Rightarrow T=\frac{m_1T_1+m_2T_2}{m_1+m_2}

Now, putting the given value in the above equation, we have

\Rightarrow T=\frac {500\times 20+750\times 30}{500+750}

\Rightarrow T=26^\circ C.

Hence, the temperature of the mixture will be 26 ^\circ C.

5 0
3 years ago
Are longer wavelengths indicative of high or low frequency?
jasenka [17]
Wavelengths would be high frequency
8 0
4 years ago
Which of the following most likely happens when blood sugar rises after eating food?
ivanzaharov [21]
Insulin is produced by the pancreas because it allows sugar from the blood to enter cells and be ised for energy
3 0
3 years ago
A 4.00-kg object traveling 20.0 m/s west collides with a 6.00-kg mass object traveling 12.0 m/s east. The collision is perfectly
nlexa [21]

Answer:

The velocity of the 4.00 kg object after the collision is 12 m/s.

Explanation:

Given that,

Mass of object m_{1} = 4.00\ kg

Velocity of object v_{1} = 20.0\ m/s

Mass of another object m_{2} = 6\ kg

Velocity of another object v_{2}= 12.0\ m/s

We need to calculate the relative velocity

v_{r}=v_{1}-v_{2}

v_{r}=20-12=8\ m/s

The relative velocity is 8 m/s in west before collision.

We know that,

In one dimensional elastic collision, the relative velocity before collision equals after collision but with opposite sign.

So, The relative velocity after collision must be 8 m/s in east.

So, The object of 6.00 kg is going 20 m/s and the object of 4.00 kg is slows down to 12 m/s.

Hence, The velocity of the 4.00 kg object after the collision is 12 m/s.

4 0
3 years ago
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