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2 years ago

If you pedal harder so the bike tires push against the ground with

Physics

1 answer:

sdas [7]2 years ago

8 0

Answer:

friction from the ground rubs on the tire which gives it more force to move forward,

Explanation: without friction the bike wont be able to use the motion to move forward. but the tires start to wear out easily.

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A Ray of light in air is incident on an air to glass boundary at an angle of 30. degrees with the normal. If the index of refrac

elena55 [62]

Answer:

Explanation:

Snell's law states:

n₁ sin θ₁ = n₂ sin θ₂

where n is the index of refraction and θ is the angle of incidence (relative to the normal).

The index of refraction of air is approximately 1. So:

1 sin 30° = 1.52 sin θ

θ ≈ 19°

5 0

3 years ago

a ship travels a port p and travels 30 km due north. then it changes course and travels 20 km in a direction 30° east of north

liq [111]

When we represent what is given to us on a coordinate plane, we have a figure as shown in the attachment.

To find the distance between P and R, we have to find the Net Displacement of the ship (brown arrow in the figure).

For that, we use the rules for Vector addition.

We see that the first displacement $D_{1}$ = 30 km (blue arrow) is along the y-axis, but the second part of the ship's journey $D_{2}$ = 20 km (red arrow) is at an angle with reference to y-axis.

So, we first find the components of the red arrow along X and Y.

Component of $D_{2}$ along X-axis is given by $D_{2x} = D_{2} Sin 30$ = 10 km

Component of $D_{2}$ along Y-axis is given by $D_{2y} = D_{2} Cos 30$ = 17.32 km

We now add all the vectors along X and along Y separately.

Net Displacement along X $D_{netX} = 10 km$

Net Displacement along Y $D_{netY} = 30 + 17.32$ = 47.32 km

Now that we have the components of the net displacement along X and Y, we make use of Pythagorean Theorem to calculate the $D_{net}$

$D_{net} = \sqrt{D_{netX} ^{2} + D_{netY} ^{2}}$

Therefore, [tex]D_{net} = 48.37 km.

Hence, the distance between the ports P and R is 48 km.

6 0

3 years ago

A car is traveling at 20 km in 15 minutes. What is its average velocity

yarga [219]

The velocity is 4374.45 m/s.
I got the answer by using v=d/t.
20,000meters / 25min= 4,374.45 m/s.

7 0

1 year ago

Given one mole of diamond vs one mole of graphite,

grandymaker [24]

Answer:

The pressure is $P= - 6.39*10^8Pa$

The temperature is $T =1218.63 K$

Explanation:

Generally Gibbs free energy is mathematically represented as

$G = E + PV -TS$

Where E is the enthalpy

PV is the pressure volume energy (i.e PV energy)

S is the entropy

T is the temperature

For stability to occur the Gibbs free energy must be equal to zero

Considering Diamond

So at temperature of T = 300 K

$E + PV - TS = 0$

making P the subject

$P = \frac{TS-E}{V}$

Now substituting 300 K for T , 2900 J for E ,

$3.42cm^3 = \frac{3.42}{1*10^6} = 3.42*10^{-6}m^3$ for V and $2.38 J/K$ for S

$P = \frac{(300 * 2.38)- 2900}{3.42*10^{-6}}$

$P= - 6.39*10^8Pa$

The negative sign signifies the direction of the pressure

Given that $P = 1*0^5Pa$

making T the subject

$T = \frac{PV+E}{S}$

Substituting into the equation

$T = \frac{1*10^5 * 3.42 *10^{-6}+2900}{2.38}$

$T =1218.63 K$

7 0

3 years ago

Read 2 more answers

A new mechanic foolishly connects an ammeter with 0.1 Ω resistance directly across a 12-V car battery with internal resistance o

NemiM [27]

Answer:

The power dissipated by the meter is 1188W

Explanation:

Here we have a circuit constituted with a power source and two resistors in series, we can calculate the power dissipated by the meter using the following formula:

$P=I^2R_m$

We first need to fin the current going through the circuit:

$I=\frac{V}{R}\\where:\\V=voltage\\R=resistance$

$R=R_s+R_m$

because they are connected in series. So:

$I=\frac{12V}{(0.01+0.1)}=109A$

$P=(109)^2*0.1=1188W$

8 0

2 years ago