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Marysya12 [62]
3 years ago
9

How do elements first form ?

Physics
1 answer:
Shtirlitz [24]3 years ago
8 0

Answer:

In the first stage, hydrogen collide and form lithium then it collide with hydrogen and forms helium then helium and lithium collide to form heavier hydrogen. After thousands of fusions of gases ( don't know how scientist keep this formula in mind ) heavier element like carbon and oxygen form.

pizz branly i nide 1 more

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a Ferrari with an initial velocity of 10 m/s, comes to a complete stop in 5 seconds, what will its acceleration be?
11111nata11111 [884]

10 m/s divided by 5 s

-2m/s/s

minus - deceleration

6 0
4 years ago
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Someone please help ! this is worth 40 points!!
makvit [3.9K]

Explanation:

  1. non uniform motion
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3 years ago
An airplane wing is designed so that the speed of the air across the top of the wing is 255 m/s when the speed of the air below
grin007 [14]
<h2>Answer:442758.96N</h2>

Explanation:

This problem is solved using Bernoulli's equation.

Let P be the pressure at a point.

Let p be the density fluid at a point.

Let v be the velocity of fluid at a point.

Bernoulli's equation states that P+\frac{1}{2}pv^{2}+pgh=constant for all points.

Lets apply the equation of a point just above the wing and to point just below the wing.

Let p_{up} be the pressure of a point just above the wing.

Let p_{do} be the pressure of a point just below the wing.

Since the aeroplane wing is flat,the heights of both the points are same.

\frac{1}{2}(1.29)(255)^{2}+p_{up}= \frac{1}{2}(1.29)(199)^{2}+p_{do}

So,p_{up}-p_{do}=\frac{1}{2}\times 1.29\times (25424)=16398.48Pa

Force is given by the product of pressure difference and area.

Given that area is 27ms^{2}.

So,lifting force is 16398.48\times 27=442758.96N

6 0
3 years ago
A girl lifts a 160-N load to a height of 1 m in 0.5 s. How much power is used to lift the load?
12345 [234]
First, find the work done. W = f*d, so 160 N * 1 m = 160 J. Then divide the work by the time to get the power. P = W/t. P = 160 J / 0.5 s = 320 W.
The answer is 320 W. Hope this helps, and have a great day! :)

8 0
3 years ago
On a snowy day, max (mass = 15 kg) pulls his little sister maya in a sled (combined mass = 20 kg) through the slippery snow. max
sesenic [268]

Work done by a given force is given by

W = F.d

here on sled two forces will do work

1. Applied force by Max

2. Frictional force due to ground

Now by force diagram of sled we can see the angle of force and displacement

work done by Max = W_1 = Fdcos\theta

W_1 = 12*5cos15

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Now similarly work done by frictional force

W_2 = Fdcos\theta

W_2 = 4*5cos180

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Now total work done on sled

W_{net}= W_1 + W2

W_{net} = 57.96 - 20 = 37.96 J

7 0
3 years ago
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