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Marysya12 [62]
4 years ago
9

How do elements first form ?

Physics
1 answer:
Shtirlitz [24]4 years ago
8 0

Answer:

In the first stage, hydrogen collide and form lithium then it collide with hydrogen and forms helium then helium and lithium collide to form heavier hydrogen. After thousands of fusions of gases ( don't know how scientist keep this formula in mind ) heavier element like carbon and oxygen form.

pizz branly i nide 1 more

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What is the current at P? <br> A 0.17A<br> B 0.26A<br> C 0.43A<br> D 1.38A
UkoKoshka [18]

Answer:

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Explanation:

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8 0
3 years ago
To drive a typical car at 40 mph on a level road for one hour requires about 3.2 × 107 J of energy. Suppose we tried to store th
tatiyna

Answer:

9000RPM

Explanation:

"Angular velocity" is directly related to kinetic energy, that is, the Kinetic energy equation would allow an approximation to the resolution investigated in the problem.

The equation for KE is given by:

KE = \frac{1}{2} lw ^ 2

Now, starting from there towards the <em>Angular equation of kinetic energy</em>, the moment of inertia (i) is used instead of mass (m), and angular velocity (w) instead of linear velocity (V)

That's how we get

KE_{Angular} = \frac{1}{2} Iw^2

calculating the inertia for a solid cylindrical disk, of

m = 400kg

r = 1.2 / 2 = 0.6m

I_{disk} = \frac{1}{2} mr^2 = (0.5) (400) (0.6)^2 = 72 kgm^2

We understand that the total kinetic energy is 3.2 * 10 ^ 7J, like this:

3.2*10^7 = \frac{1}{2} Iw^2 = (0.5) (72) w^2 = 36w^2w^2 = 3.2*10^7 / 36 = 0.0888*10^7 = 88.8*10^4

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Thus,

943 rad / s ≈ 9000 rpm

6 0
3 years ago
An object is placed 9.5 cm in front of a convex spherical mirror. Its image forms 3.2 cm behind the mirror. What is the radius o
o-na [289]

Using the mirror formula.

1/v + 1/u = 1/f

1/9.5 + 1/3.2 = 1/f

1/f = 3.2 + 9.5 / 9.5 * 3.2

1/f = 4.82 cm

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Radius = 2 x 4.82

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8 0
4 years ago
Read 2 more answers
6.) What is the missing element?<br><br> a. Hydrogen<br> b. Helium<br> c. Carbon<br> d. Nitrogen
IrinaK [193]

Answer:

It's nitrogen. Specifically, this is the alpha emission of an N-15 isotope.

8 0
3 years ago
A 25 N force pushes a block across a surface for 6 m.How much work is done by the applied force?
hram777 [196]

Answer: 150 joules

Explanation:

Force applied on a block = 25N

Distance moved by block = 6 m

Workdone = ?

Recall that work is done when force is applied on an object over a distance. And it is measured in joules.

I.e Workdone = Force X Distance

= 25N x 6 metres

= 150 joules

Thus, 150 joules of work is done by the applied force.

4 0
4 years ago
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