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3 years ago

Anybody wanna play among us?

Physics

2 answers:

kherson [118]3 years ago

8 0

Answer:

yess

Explanation:

Grace [21]3 years ago

3 0

Answer:

yes me

<h3>mark me brainliest</h3>

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If the dartboard below is used to model an atom, which subatomic particles would be located at Z? *

Anna11 [10]

I know that protons and neutrons are located at the center of an atom, so the correct answer is D

7 0

3 years ago

You set a tuning fork into vibration at a frequency of 723 Hz and then drop it off the roof of the Physics building where the ac

zaharov [31]

Answer:

Explanation:

Given

Original Frequency $f=723\ Hz$

apparent Frequency $f'=697\ Hz$

There is change in frequency whenever source move relative to the observer.

From Doppler effect we can write as

$f'=f\cdot \frac{v-v_o}{v+v_s}$

where

$f'=$ apparent frequency

v=velocity of sound in the given media

$v_s=$ velocity of source

$v_0=$ velocity of observer

here $v_0=0$

$697=723\cdot (\frac{343-0}{343+v_s})$

$v_s=(\frac{f}{f'}-1)v$

$v_s=(\frac{723}{697}-1)\cdot 343$

$v_s=12.79\approx 12.8\ m/s$

i.e.fork acquired a velocity of $12.8 m/s$

distance traveled by fork is given by

$v^2-u^2=2as$

where v=final velocity

u=initial velocity

a=acceleration

s=displacement

$v_s^2-0=2\times 9.8\times s$

$s=\frac{12.8^2}{2\times 9.8}$

$s=8.35\ m$

5 0

2 years ago

What is the fundamental cause of air circulation in earths atmosphere

Digiron [165]

<span>A differences in the warmth, or moisture level as well as neighbouring areas of pressure in </span>air cause air<span> to circulate. in the earth's atmosphere.</span>

4 0

3 years ago

Light of wavelength 478 nm in air falls on two slits 6.53 mm apart. The slits are immersed in water, as is a viewing screen 30.8

cluponka [151]

The distance between the two fringes is 0.0225 mm.

<u>Explanation:</u>

As per Young's double slit experiment, the distance between the fringes can be observed for the bright constructive interference fringes. So if we know the distance between the separation of slits. the distance of the mirror placed away from the slit, then the distance between two fringes can be observed using the below formula.

$y=\frac{m\times wavelength\times D}{d}$

Here y is the distance between the fringes on screen, D is the distance of the screen from the slits and d is the distance between the slits. Also m is the order of the interference which is generally considered as 1.

So, in the present case, D = 30.8 cm = 0.308 m, d = 6.53×10⁻³ m, wavelength = 478 nm and m = 1.

So, $y = \frac{1\times 478\times 10^{-9} \times 0.308}{6.53\times 10^{-3} }$