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3 years ago

The Doppler effect changes the

Chemistry

2 answers:

postnew [5]3 years ago

8 0

The best answer that I would would be B

dem82 [27]3 years ago

3 0

A) Frequency due to motion

As you are moving toward the object that is making the sound the frequency is higher. When you begin to move away the frequency lowers.

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Match the following associations. Exothermic or endothermic

Alekssandra [29.7K]

Answer:

1) ∆H is positive $\Rightarrow$ Endothermic

2) $E_p>E_r$ $\Rightarrow$ Endothermic

3) Energy is absorbed $\Rightarrow$ Endothermic

4) $E_r>E_p$ $\Rightarrow$ Exothermic

5) ∆H is negtive $\Rightarrow$ Exothermic

Explanation:

∆H is called as enthalpy change

It is also called as Heat of reaction

Energy is required for the bond to break a bond.

Energy is released when a bond is formed.

$H_2+Cl_2>2HCl$

that is

$H-H+Cl-Cl>2H-Cl$

We see in this equation, bonds between hydrogen and chlorine molecules gets broken and on the right side bond is formed in HCl.

If energy of products greater than energy of reactants then the reaction enthalpy change is endothermic .

If energy of products lesser than energy of reactants then the reaction enthalpy change is exothermic .

For example

$\Delta H=E_p-E_r$

$=30KJ-20KJ$

$=+10KJ$

(positive hence endothermic)

$\Delta H=E_p-E_r$

$=10KJ-40KJ$

$=-30KJ$

(negative hence exothermic)

8 0

3 years ago

What is the IUPAC name of the following compound?

inn [45]

Answer:

2,6–dimethylcyclohexanol

Explanation:

To name the compound given in the question above, we must first obtain the following:

1. Determine the functional group of the compound.

2. Locate the longest continuous carbon chain.

3. Identify the substituent group attached to the compound.

4. Locate the position of the substituent group.

5. Combine the above to obtain the name of the compound.

Now, we shall determine the name IUPAC name of the compound. This can be obtained as follow:

1. The compound contains the –OH group. Thus, the compound is an alcohol.

2. The compound is a cyclic compound with six carbon forming the ring. Thus, the parent name of the compound is cyclohexane. Thus, the presence of the –OH group changes the parent name of the compound to cyclohexanol.

3. The substituent group attached to the compound is methyl (–CH₃)

NOTE: There are two –CH₃ groups attached to the compound.

4. The position of the 1st –CH₃ group is at carbon 2, while the 2nd is at carbon 6.

NOTE: Counting is done from the carbon bearing the functional group.

5. Therefore, the name of the compound is:

2,6–dimethylcyclohexanol

7 0

3 years ago

How many mL of a 0.375 M solution can be made from 35 g of calcium phosphate?

andrew11 [14]

Answer:

300 mL

Explanation:

the unit formula of calcium phosphate is Ca3(PO4)2

molar mass of Ca3(PO4)2 = (3×40 + 2×31 + 8×16) g/mol = 310 g/mol

n = m/M = 35 g/(310 g/mol)

c = n/V

V = n/c = [35 g/(310 g/mol)]/0.375 mol/L

V = 0.30 L = 300 mL

3 0

2 years ago

What is the mass of 6.02 x 1022 atoms of Xenon? HELP!!!!!

il63 [147K]

So 6.02*10^22 is avogadro constant, which is the amount of atoms in one mole. If you look Xenon up in the periodic table you will find it's mass given 131,293, which is grams per 1 mole.

8 0

3 years ago

A tank of 0.1m3 volume contains air at 25∘C and 101.33 kPa. The tank is connected to a compressed-air line which supplies air at

Dmitriy789 [7]

Answer:

Amount of Energy = 23,467.9278J

Explanation:

Given

Cv = 5/2R

Cp = 7/2R wjere R = Boltzmann constant = 8.314

The energy balance in the tank is given as

∆U = Q + W

According to the first law of thermodynamics

In the question, it can be observed that the volume of the reactor is unaltered

So, dV = W = 0.

The Internal energy to keep the tank's constant temperature is given as

∆U = Cv((45°C) - (25°C))

∆U = Cv((45 + 273) - (25 + 273))

∆U = Cv(20)

∆U = 5/2 * 8.314 * 20

∆U = 415.7 J/mol

Before calculating the heat loss of the tank, we must first calculate the amount of moles of gas that entered the tank where P1 = 101.33 kPa

The Initial mole is calculated as

(P * V)/(R * T)

Where P = P1 = 101.33kPa = 101330Pa

V = Volume of Tank = 0.1m³

R = 8.314J/molK

T = Initial Temperature = 25 + 273 = 298K

So, n = (101330 * 0.1)/(8.314*298)

n = 4.089891232222

n = 4.089

Then we Calculate the final moles at P2 = 1500kPa = 1500000Pa

V = Volume of Tank = 0.1m³

R = 8.314J/molK

T = Initial Temperature = 25 + 273 = 298K

n = (1500000 * 0.1)/(8.314*298)

n = 60.54314465936812

n = 60.543

So, tue moles that entered the tank is ∆n

∆n = 60.543 - 4.089

∆n = 56.454

Amount of Energy is then calculated as:(∆n)(U)

Q = 415.7 * 56.454

Q = 23,467.9278J

3 0

3 years ago