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GrogVix [38]
3 years ago
14

Please help me on this

Physics
1 answer:
Dafna1 [17]3 years ago
5 0
I’m pretty sure the answer is A
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An actor has a mass of 70 kg. Gravitational field strength = 9.8 N/kg. Use the following equation to calculate the weight of the
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This is a way of measuring how much gravity there is. The formula is: weight/mass = gravitational field strength.

Gravitational field strength = Weight/mass unit is N/kg

Weight = mass x gravitational field strength unit is N

On Earth the gravitational field strength is 10 N/kg. Other planets have different gravitational field strengths. The Moon has a gravitational field strength of 1.6 N/kg. You might have seen films of astronauts leaping high on the moon.

Here on Earth, if I jump I am pulled back to ground by gravity. What is my weight? My mass is 80kg and if we multiply by gravitational field strength (10N/kg) - my weight is 800N. Now if I go to the moon, my mass will be the same, 80kg. We multiply that by the moon's gravitational field strength, which is 1.6 N/ kg. That means my weight on the moon is 128N. So I have different weights on the Earth and on the Moon. That's why astronauts can jump high into the air on the moon - they're lighter up there.

Jupiter is a very large planet with strong gravitational field strength of 25 N/ kg. My body is 80kg. If I go to Jupiter my weight is going to be 25 x 80 = 2,000 N. That means I wouldn't be able to get off the ground or stand up straight! I would probably be lying down all the time there. So weight varies depending on which planet you are on. You can find out more yourself by looking up tables of weight on different planets.
8 0
2 years ago
Calculate the magnitude of the effort in the given​
Otrada [13]
Moment = Force x Distance from pívot
500x0.5=2.5 x effort
250= 2.5 x effort
effort = 250/2.5= 100N
8 0
3 years ago
Why would you wanna know a cure for all sickness.?
Alchen [17]

Answer:

because if someone close to u gets sick you would know how to cure it

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What factors contribute to global winds identify areas where winds are weak
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<span>The factors that influence wind and contribute to global winds are pressure gradient, Rossby waves and jet streams, and local weather conditions.</span>
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3 years ago
Read 2 more answers
A car's bumper is designed to withstand a 7.20 km/h (2.0 m/s) collision with an immovable object without damage to the body of t
ollegr [7]

Answer:

8512 N

Explanation:

From the work energy theorem we know that: The net work done on a particle equals the change in the particles kinetic energy:

W=\Delta K=K_{f}-K_{i} \\&#10;\\qquad \begin{array}{r}&#10;W=F \cdot d, \Delta K=\frac{1}{2} m v_{f}^{2}-\frac{1}{2} m v_{i}^{2} \\&#10;F \cdot d=\frac{1}{2} m v_{f}^{2}-\frac{1}{2} m v_{i}^{2}

Where:

-W is the work done by the force.

- F is the force actin on the.

- d is the distance travelled.

- m is the mass of the car.

- v_{f}, v_{i} are the final and the initial velocity of the car

K_{f}, K_{i} are the final and the kinetic energy of the car.

Givens: m=830 \mathrm{~kg}, v_{i}=2 \mathrm{~m} / \mathrm{s}, v_{f}=0 \mathrm{~km} / \mathrm{h}, d=0.195 \mathrm{~m}

Plugging known information to get:

F \cdot d &=\frac{1}{2} m v_{f}^{2}-\frac{1}{2} m v_{i}^{2} \\&#10;F &=\frac{\frac{1}{2} m v_{f}^{2}-\frac{1}{2} m v_{i}^{2}}{d} \\&#10;&=\frac{0-\frac{1}{2} \times 830 \times 2^{2}}{0.195} \\&#10;&=8.512 \times 10^{3} \\&#10;F &=8.512 \times 10^{3} \mathrm{~N}

8 0
3 years ago
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