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frosja888 [35]
3 years ago
5

What are the correct coefficients for the reaction below:

Chemistry
1 answer:
77julia77 [94]3 years ago
7 0

C was the answer i had and it was right


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. A sample of crude oil has a density of 0.87 g/mL. What volume (in liters) does a 3.6 kg sample of this oil occupy
gayaneshka [121]

Answer:

The volume is 4.13793 L

Explanation:

Density is a quantity that expresses the relationship between the mass and the volume of a body, so it is defined as the quotient between the mass and the volume of a body:

density=\frac{mass}{volume}

Density is a characteristic property of every body or substance.

The most commonly used units of density are \frac{kg}{m^{3} } or \frac{g}{cm^{3} } for solids, and \frac{kg}{L} or \frac{g}{mL} for liquids and gases.

In this case, you know:

  • density= 0.87 \frac{g}{mL}
  • mass= 3.6 kg= 3,600 g (being 1 kg=1,000 g)
  • volume= ?

Replacing:

0.87\frac{g}{mL} =\frac{3,600 g}{volume}

Solving:

volume =\frac{3,600 g}{0.87\frac{g}{mL}}

volume= 4,137.93 mL

Being 1,000 mL=1 L, then volume= 4,137.93 mL= 4.13793 L

<u><em>The volume is 4.13793 L</em></u>

5 0
3 years ago
A4 kg object is being pulled to the east by a 6 N force. What is the object's<br> acceleration?
Dahasolnce [82]

1.5 ms⁻²

Explanation:

We understand that Force is also given as mass * acceleration;

F = Ma

If force is 6N and the mass is 4kg of the object, the a can be evaluated as follows;

6 = 4a

6/4 = a

1.5 = a

= 1.5m/s²

4 0
3 years ago
1. A 1500kg car is being lifted by a hydraulic jack attached to a flat plate. Underneath the plate is
AURORKA [14]

Answer:

the pressure in the pipe in the case when there is no net force on the car is  81,726 N/m^2

Explanation:

a. The computation of the pressure in the pipe in the case when there is no net force on the car is shown below

As we know that

Pressure = F ÷ area

Also

F = mg

Now

= (1500 × 9.8) ÷π (0.24)^2

= 81,726 N/m^2

Hence, the pressure in the pipe in the case when there is no net force on the car is  81,726 N/m^2

5 0
3 years ago
A. CH,0, molar mass is 90 g/mol
Luba_88 [7]

what is that i cant see anything?

7 0
3 years ago
After 11.5 days, 12.5% of a sample of radon-222 that originally weighed 42g remains. What is the half-life of this isotope?
Bond [772]
Half-life is defined as the amount of time it takes a given quantity to decrease to half of its initial value.  The equation to describe the decay is
Nt=N0(1/2) ^{t/t(1/2)}  where N0 is the initial quantity, Nt is the remaining quantity after time t, t1/2 is the half-time.  So work out the equation, t1/2 = t (-ln2)/ln(Nt/N0) = 11.5*(-ln2)/ln(12.5/100) = 3.83 days
5 0
3 years ago
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