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irga5000 [103]
3 years ago
7

What is the molarity of the bleach solution of slide 28 (7.4% NaOCl by mass, density 1.12 g.cm-3)?

Chemistry
2 answers:
katrin [286]3 years ago
5 0

Answer:

\large \boxed{\text{1.11 mol $\cdot$ dm}^{-3}}

Explanation:

Molar concentration = moles/cubic decimetres

So, we need both the number of moles and the volume.

1. Volume

Assume a volume of 1 dm³.

That takes care of that.

2. Moles of NaOCl

(a) Mass of solution

\text{ Mass of solution} = \text{1000 cm}^{3} \times \dfrac{\text{1.12 g solution}}{\text{1 cm}^{3}} = \text{1120 g solution}

(b) Mass of NaOCl

\text{Mass of NaOCl} = \text{1120 g solution}\times \dfrac{\text{7.4 g NaOCl}}{\text{100 g solution}} = \text{82.9 g NaOCl}

(c) Moles of NaOCl

\text{Moles of NaOCl} = \text{82.9 g NaOCl} \times \dfrac{\text{1 mol NaOCl}}{\text{74.44 g NaOCl}} = \text{1.11 mol NaOCl}

(d) Molar concentration

\text{Molar concentration} = \ \dfrac{\text{1.11 mol NaOCl}}{\text{1 dm}^{3}} = \textbf{1.11 mol $\cdot$ dm}^{\mathbf{-3}}\\\\\text{The molar concentration of the NaOCl is $\large \boxed{\textbf{1.11 mol $\cdot$ dm}^{\mathbf{-3}}}$}

Anuta_ua [19.1K]3 years ago
3 0

Answer:

Molarity of solution is 1.10x10⁻³ M

Explanation:

Solute NaOCl

7.4% by mass means, that in 100 grams of solution, we have 7.4 g of solute.

Molar mass of NaOCl = 74.45 g/m

Mol = Mass / Molar mass

7.4 g / 74.45 g/m = 0.099 moles

Density of solution = 1.12 g/mL

Density = Mass / volume

1.12g/mL = 100 g / volume

Volume = 100 g / 1.12g/mL = 89.3 mL

Molarity = mol /L

89.3 mL = 0.0893 L

0.099 moles / 0.0893 L = 1.10x10⁻³ M

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How do we balance Zn + HNO3 Zn(NO3)2 + NO + H20​
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3Zn + 8HNO₃⇒ 3Zn(NO₃)₂ + 2NO + 4H₂O

<h3>Further explanation </h3>

Equalization of chemical reaction equations can be done using variables. Steps in equalizing the reaction equation:  

  • 1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c etc.  
  • 2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index between reactant and product  
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For gas combustion reaction which is a reaction of hydrocarbons with oxygen produces CO₂ and H₂O (water vapor). can use steps:  

Balancing C atoms, H and the last O atoms

Reaction

Zn + HNO₃⇒ Zn(NO₃)₂ + NO + H₂O

  • 1. gives a coefficient

aZn + bHNO₃⇒ Zn(NO₃)₂ + cNO + dH₂O

  • 2. make an equation

Zn : left = a, right =1 ⇒a=1

H : left = b, right = 2d⇒ b=2d (eq 1)

N : left = b, right = 2+c⇒b=2+c (eq 2)

O : left = 3b, right = 6+c+d ⇒3b=6+c+d(eq 3)

  • From eq 1 and eq 3

3(2d)=6+c+d

6d=6+c+d

5d=6+c (eq 4)

  • From eq 2 and eq 3

3(2+c)=6+c+d

6+3c=6+c+d

2c=d (eq 5)

  • From eq 4 and eq 5

5(2c)=6+c

10c=6+c

9c=6

c = 2/3

  • input eq 5

d = 2 x 2/3

d = 4/3

  • input eq 1

b = 2 x 4/3

b = 8/3

The equation

aZn + bHNO₃⇒ Zn(NO₃)₂ + cNO + dH₂O to

Zn + 8/3HNO₃⇒ Zn(NO₃)₂ + 2/3NO + 4/3H₂O x 3

3Zn + 8HNO₃⇒ 3Zn(NO₃)₂ + 2NO + 4H₂O

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What is the speed of light of an orange light with a wavelength of 600nm and a frequency of 5.00x1014?
vovangra [49]

Answer:

3 × 10^8 m/s

Explanation:

The wavelength, can be calculated by using the following formula;

λ = v/f

Where;

λ = wavelength (m)

v = velocity/speed of light (m/s)

f = frequency (Hz)

According to the provided information in this question, λ = 600nm i.e. 600 × 10^-9m, f = 5.00 x 10^14 Hz

Hence, using λ = v/f

v = λ × f

v = 600 × 10^-9 × 5.00 x 10^14

v = 6 × 10^-7 × 5.00 x 10^14

v = 30 × 10^(-7 + 14)

v = 30 × 10^ (7)

v = 3 × 10^8 m/s

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