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Fudgin [204]
2 years ago
5

How can u create a fair test? Short answer only:

Physics
2 answers:
omeli [17]2 years ago
7 0

Answer:

A way you can create a fair test by making sure that you change one factor at a time while keeping all other conditions the same.

Explanation:

Hope it helps! Have a great day!

Lilac~

Crazy boy [7]2 years ago
5 0

Answer:

making sure that you change one factor at a time while keeping all other conditions the same

Explanation:

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krek1111 [17]

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C

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3 years ago
The temperature of a smelting furnace is found to be 2000 degree Celsius.find the temperature on Fahrenheit scale​
Dima020 [189]

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3632.

Explanation:

Based on the formula:

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6 0
3 years ago
The energy from 0.015 moles of octane was used to heat 250 grams of water. The temperature of the water rose from 293.0 K to 371
arsen [322]

Answer : The correct option is, (B) -5448 kJ/mol

Explanation :

First we have to calculate the heat required by water.

q=m\times c\times (T_2-T_1)

where,

q = heat required by water = ?

m = mass of water = 250 g

c = specific heat capacity of water = 4.18J/g.K

T_1 = initial temperature of water = 293.0 K

T_2 = final temperature of water = 371.2 K

Now put all the given values in the above formula, we get:

q=250g\times 4.18J/g.K\times (371.2-293.0)K

q=81719J

Now we have to calculate the enthalpy of combustion of octane.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy of combustion of octane = ?

q = heat released = -81719 J

n = moles of octane = 0.015 moles

Now put all the given values in the above formula, we get:

\Delta H=\frac{-81719J}{0.015mole}

\Delta H=-5447933.333J/mol=-5447.9kJ/mol\approx -5448kJ/mol

Therefore, the enthalpy of combustion of octane is -5448 kJ/mol.

5 0
4 years ago
Determine the relationship between neutron stars and black holes
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Answer:

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Explanation:

7 0
3 years ago
Why do electrons flow threw a wire
Zolol [24]

Answer:

When electric voltage is applied, an electric field within the metal triggers the movement of the electrons, making them shift from one end to another end of the conductor. Electrons will move toward the positive side.

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2 years ago
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