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Aleksandr-060686 [28]
3 years ago
6

How does newton’s third law effect bowling?

Chemistry
2 answers:
Sedaia [141]3 years ago
7 0

Answer: His third law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A. Notice that the forces are exerted on different objects.

Explanation: this means that when you throw the ball the wind pushes against the ball and so does the bolling pints.

Misha Larkins [42]3 years ago
4 0

Answer:

The bowling ball will remain in motion until an unbalanced force acts on the bowling ball. ... When the ball hits the pins, they push on the ball with the same amount of force in the opposite direction. This means that the ball will slow down, and the pins will fall, which is the reaction.

Explanation:

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Chemical Quantities "Molar Mass - 2 step" - Wksh #3 Directions: Use dimensional analysis to perform the following calculations.
fomenos

There are about 1.27  × 10^23 molecules present in 13.5 g of SO2.

<h3>What are molecules?</h3>

A molecule is the simplest part of a compound that have independent existence.

Number of moles of sulfur dioxide = 13.5 g/64 g/mol = 0.211 moles

If 1 mole of SO2 contains 6.02 × 10^23 molecules

0.211 moles of SO2 contains 0.211 moles × 6.02 × 10^23 molecules/1 mole

= 1.27  × 10^23 molecules

32 g of sulfur contains 6.02 × 10^23 atoms

x g of sulfur contains  2.23 x 10^23

x = 32 × 2.23 x 10^23 /6.02 × 10^23

x = 11.85 g

6.02 × 10^23 formula units has a mass of AgF = 127 g

x formula units has a mass of  = 42.15 g

x = 6.02 × 10^23 × 42.15/127

x = 2 × 10^23 formula units

6.02 × 10^23 formula units of Fe2O3 has a mass of 160 g

8.83 x 10^23 formula units of Fe2O3 has a mass of 8.83 x 10^23 x 160 g/6.02 × 10^23

x = 235 g

Learn more about formula unit: brainly.com/question/19293051

6 0
2 years ago
Products and reactants are used and created at the same rate when a reaction is at this stage
V125BC [204]

This means that the reaction is in dynamic equilibrium.

Hope this helps because I don't really know the question you asked :)))

7 0
4 years ago
Read 2 more answers
How many moles of MgCO3 are in 2.57g of MgCO3?
Sveta_85 [38]

Answer:

0.0305 moles of MgCO₃

Explanation:

In order to solve this problem, we first need to calculate the molecular weight of MgCO₃:

  • MgCO₃ MW = Atomic mass Mg + Atomic mass C + (Atomic mass O)*3
  • MgCO₃ MW = 24.3 + 12 + 16*3 = 84.3 g/mol

Finally we <u>divide the mass by the molecular weight</u>, to calculate the <em>number of moles</em>:

  • 2.57 g MgCO₃ ÷ 84.3 g/mol = 0.0305 moles.
7 0
3 years ago
Identify the substance which has same number of molecules in 14g N2
valentina_108 [34]
We need to know the number of molecules which is number of moles * Avogadro’s number
So
We need to compare number of moles because Avogadro’s numbers is constant for all
We’ll start with Nitrogen gas : 14g/28g.mol=0.5 mole

For NH3 : 3.4g / (14+3)g.mol= 0.2 mol
For NO. : 15g/(14+16)g.mol = 0.5 mol
For O2 : 64g/32 g.mol = 2 mol
For SO2: 32g /( 32+32) g.mol = 0.5mol
For H2. : 1g/ 2g.mol = 0.5 mol

So
H2& SO2 & NO have the same number of moles of N2 and the same number of molecules of N2
4 0
3 years ago
The symbol for the element in period 2 group 13 is
Natalija [7]

Answer:

Boron

Explanation:

Using the periodic table we can see that Period 2 represents the second row. Group 13 indicates the 13th column.

7 0
3 years ago
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