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Aleksandr-060686 [28]
2 years ago
6

How does newton’s third law effect bowling?

Chemistry
2 answers:
Sedaia [141]2 years ago
7 0

Answer: His third law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A. Notice that the forces are exerted on different objects.

Explanation: this means that when you throw the ball the wind pushes against the ball and so does the bolling pints.

Misha Larkins [42]2 years ago
4 0

Answer:

The bowling ball will remain in motion until an unbalanced force acts on the bowling ball. ... When the ball hits the pins, they push on the ball with the same amount of force in the opposite direction. This means that the ball will slow down, and the pins will fall, which is the reaction.

Explanation:

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The differemt isotopes that differ in atomic mass

Explanation:

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What is it called when scientists write out a compound such as two hydrogen and one oxygen? PLEASE HELP
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A compound is when two or more elements are joined together. The compound that is created with two hydrogens and one oxygen is h2o or water.
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3 years ago
A liquid that evaporates at a slow rate exhibits __________.
Marizza181 [45]
Strong internolecurar forces (A) hope it helps
3 0
3 years ago
Consider the following system at equilibrium:
alexgriva [62]

Answer:

A - Increase (R), Decrease (P), Decrease(q), Triple both (Q) and (R)

B - Increase(P), Increase(q), Decrease (R)

C - Triple (P) and reduce (q) to one third

Explanation:

<em>According to Le Chatelier principle, when a system is in equilibrium and one of the constraints that affect the rate of reaction is applied, the equilibrium will shift so as to annul the effects of the constraint.</em>

P and Q are reactants, an increase in either or both without an equally measurable increase in R (a product) will shift the equilibrium to the right. Also, any decrease in R without a corresponding decrease in either or both of P and Q will shift the equilibrium to the right. Hence, Increase(P), Increase(q), and Decrease (R) will shift the equilibrium to the right.

In the same vein, any increase in R without a corresponding increase in P and Q will shift the equilibrium to the left. The same goes for any decrease in either or both of P and Q without a counter-decrease in R will shift the equilibrium to the left. Hence, Increase (R), Decrease (P), Decrease(q), and Triple both (Q) and (R) will shift the equilibrium to the left.

Any increase or decrease in P with a commensurable decrease or increase in Q (or vice versa) with R remaining constant will create no shift in the equilibrium. Hence, Triple (P) and reduce (q) to one third will create no shift in the equilibrium.

6 0
3 years ago
What needs to happen for the equation CH4 + O2 → CO2 + H2O to be balanced?
worty [1.4K]
B. This is because the Hydrogen and Oxygen need balanced out.

Current-

C-1            |        C-1
H-4            |         H-2
O-2            |         O-3


Adding a coefficient of 2 before oxygen in the reactants and H2O in the products would balance this equation

<span>CH4 + 2O2 → CO2 + 2H2O</span>
C-1            |        C-1
H-4            |         H-4
O-4            |        O-4


4 0
3 years ago
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