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amid [387]
2 years ago
8

A cyclist accelerates from a velocity of 10 miles/hour east until reaching a velocity of 20 miles/hour east in 5 seconds. What w

as the cyclist's acceleration?
Physics
1 answer:
Sliva [168]2 years ago
3 0

Answer:

a = 0.894\ m/s^2

Explanation:

<u>Motion with Constant Acceleration</u>

A body moves with constant acceleration when the speed changes uniformly in time. The equation used to find the final speed vf is

v_f=v_o+at

Where vo is the initial speed, a is the acceleration, and t is the time.

The cyclist has an initial speed of vo=10 miles/hour and ends up at vf=20 miles/hour in t=5 seconds.

Both speeds are given in miles/hour and we must convert it to m/s:

1 mile/hour = 0.44704 m/s

10 mile/hour = 4.47 m/s

20 mile/hour = 8.94 m/s

The acceleration is calculated by solving for a:

\displaystyle a=\frac{v_f-v_o}{t}

\displaystyle a=\frac{8.94-4.47}{5}

a = 0.894\ m/s^2

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55 ohms

Explanation:

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How can we define force?
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Explanation:

A force is a push or pull upon an object resulting from the object's interaction with another object. Whenever there is an interaction between two objects, there is a force upon each of the objects. When the interaction ceases, the two objects no longer experience the force.

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A bowling ball of mass m = 1.7 kg drops from a height h = 14.2 m. A semi-circular tube of radius r = 6.2 m rest centered on a sc
marshall27 [118]

Answer:

W_net = mg + 2mgh/r

Explanation:

The forces applied in this motion of the bowling ball are both gravitational and centripetal forces.

Now, gravitational force is; F_g = mg

While centripetal force is; F_c = mv²/r

Since we want to express the net force in terms of the variables in the statement and we are not given "v", let's find an expression of v with the variables given.

Now, from Newton's equation of motion, at initial velocity of 0, v² = 2gh.

Thus;

F_c = 2mgh/r

Where;

m is ball mass

r is tube radius

h is fall height

Thus, the net force will be;

F_net = F_g + F_c

Now, Net force would be equal to the net weight that will be read on the scale.

Thus;

W_net = F_net = F_g + F_c

W_net = mg + 2mgh/r

8 0
3 years ago
Three astronauts guide a 100 kg asteroid safely away from their space capsule. The first astronaut pushes with a 35 N force dire
svlad2 [7]

The magnitude of the net force exerted by the three astronauts is 84.5 N and the rate at which the asteroid's velocity changes is 0.845 m/s².

The given parameters;

  • <em>mass of the asteroid = 100 kg</em>
  • <em>force by first astronaut = 35 N, at 45 degrees below x -axis</em>
  • <em>force by second astronaut = 35 N, at 45 degrees above x-axis</em>
  • <em>force by third  astronaut = 35 N, at 0 degrees on x-axis</em>

The resultant horizontal force applied by the three astronauts on the asteroid is calculated as;

Fₓ = 35cos(45) + 35cos(45) + 35cos(0)

Fₓ = 84.5 N

The rate at which the asteroid's velocity changes is calculated as;

F = ma = m\frac{\Delta v}{\Delta t} \\\\\frac{\Delta v}{\Delta t}  = \frac{F}{m} \\\\\frac{\Delta v}{\Delta t}  = \frac{84.5}{100} \\\\\frac{\Delta v}{\Delta t}  = 0.845 \ m/s^2

Thus, the magnitude of the net force exerted by the three astronauts is 84.5 N and the rate at which the asteroid's velocity changes is 0.845 m/s².

Learn more here: brainly.com/question/20407089

4 0
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