A plane mirror always forms a virtual image. the image and the object are the same distance from a flat mirror, the image size is the same as the object, and the image is upright!
From the starting depth to the surface, the vertical distance is 35 ft.
From the surface to the peak of the jump, the vertical distance is 27 ft.
From the peak of the jump to the surface, the vertical distance is 27 ft.
From the surface to the ending depth, the vertical distance is 18 ft.
Then the total vertical distance is ...
35 ft + 27 ft + 27 ft + 18 ft = 107 ft
Answer:
Explanation:
Stored energy in spring = 1/2 k x² , k is spring constant , x is compression.
= 1/2 x 8 x (5.7 x 10⁻²)²
= 129.96 x 10⁻⁴ J
Energy lost due to friction = force x distance
= .035 x .17
= .00595 J
Energy used in providing kinetic energy to projectile.
129.96 x 10⁻⁴ - .00595
.012996 - .00595
= .007046 J
So
1/2 m v² = .007046
v² = .007046 x 2 / .0059
= 2.3885
v = 1.545 m /s