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andrew-mc [135]
3 years ago
10

Which statement correctly describes these electric field lines

Physics
2 answers:
JulijaS [17]3 years ago
8 0

Answer:

ok

Explanation:

the correct answer is C please follow me

GrogVix [38]3 years ago
4 0
C is the correct answer : source A is Negatively charged source B is positively charged.
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Earth attracts a person with a gravitational force of 7.0 × 102 newtons. What is the magnitude of the force with which the indiv
Anuta_ua [19.1K]
This is a good time to review Newton's 3rd law of motion:
"For every action, there is an equal and opposite reaction."

Gravitational force always acts in pairs.
Whatever force the Earth attracts something with,
the thing attracts the Earth with exactly the same force.

If Earth attracts a person with a gravitational force of <span><span>7.0 × 10² </span>newtons,
the person attracts Earth with a gravitational force of 7.0 × 10² newtons.

Your weight on Earth is the same as the Earth's weight on you !
</span>
5 0
4 years ago
As Clinton walks he pushes his shoe against the track.
Valentin [98]

Answer:A:The track pushes back on Clinton's shoe with the same force.

Explanation:According to Newton's third law of motion, for every action force there is an equal and opposite reaction force. In this case, the action force is Clinton's shoe pushing on the track. As this happens, there is an equal and opposite reaction force in which the track pushes back on Clinton's shoe with the same force.

4 0
3 years ago
A rock is sitting at the edge of a flat merry-go-round at a distance of 1.6 meters from the center. The coefficient of static fr
PSYCHO15rus [73]

Answer:

ω = 2.1 rad/sec

Explanation:

  • As the rock is moving along with the merry-go-round, in a circular trajectory, there must be an external force, keeping it on track.
  • This force, that changes the direction of the rock but not its speed, is the centripetal force, and aims always towards the center of the circle.
  • Now, we need to ask ourselves: what supplies this force?
  • In this case, the only force acting on the rock that could do it, is the friction force, more precisely, the static friction force.
  • We know that this force can be expressed as follows:

       f_{frs} = \mu_{s} * F_{n} (1)

      where μs = coefficient of static friction between the rock and the merry-

      go-round surface = 0.7, and Fn = normal force.

  • In this case, as the surface is horizontal, and the rock is not accelerated in the vertical direction, this force in magnitude must be equal to the weight of the rock, as follows:
  • Fn = m*g (2)
  • This static friction force is just the same as the centripetal force.
  • The centripetal force depends on the square of the angular velocity and the radius of the trajectory, as follows:

       F_{c} = m* \omega^{2}*r (3)

  • Since (1) is equal to (3), replacing (2) in (1) and solving for ω, we get:

       \omega = \sqrt{\frac{\mu_{s} * g}{r} } = \sqrt{\frac{0.7*9.8m/s2}{1.6m}} = 2.1 rad/sec

  • This is the minimum angular velocity that would cause the rock to begin sliding off, due to that if it is larger than this value , the centripetal force will be larger that the static friction force, which will become a kinetic friction force, causing the rock to slide off.
4 0
3 years ago
In uniform circular motion, which of the following are constant:Check all that apply.Check all that apply.the speed is constantt
AlladinOne [14]

Answer:

The speed, magnitude of the velocity, magnitude of the angular velocity, magnitude of the centripetal acceleration, magnitude of the net force and direction of the angular velocity are constant.

Explanation:

In uniform circular motion we have a centripetal acceleration of constant magnitude but changing direction (since it points to the center of the circle from the object). The same goes for the net (centripetal) force since F=ma. This makes the magnitude of the velocity (speed) constant but its direction changes, although keeping spinning in the same direction, which makes its angular velocity constant in both magnitude and direction.

3 0
4 years ago
Read 2 more answers
a block measuring 20cm by 10cm by 5cm rests on a flat surface. The block has a weight of 3N. Determine the maximum pressure it e
Lady_Fox [76]
Max preassure = force / min area
= 3N / 0.1 x 0.05
= 600N/m(squared)
Copy off of the picture below itll help better, its what someone sent me when i asked this question

4 0
4 years ago
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