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3 years ago

How long will it take for a body

Physics

1 answer:

Daniel [21]3 years ago

7 0

We are given:

Initial velocity (u) = 0 m/s [starting from rest]

Final velocity (v) = 10 m/s

Acceleration (a) = 2 m/s²

Time taken = t

Solving for time taken:

v = u + at [first equation of motion]

10 = 0 + (2)(t) [plugging the values]

10 = 2t

t = 5 seconds

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Jim is driving a 2268-kg pickup truck at 15.0 m/s and releases his foot from the accelerator pedal. The car eventually stops due

HACTEHA [7]

Answer:

255150 J

364.50233 m

Explanation:

f = Frictional force = 700 N

m = Mass of truck = 2268 kg

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

The kinetic energy is given by

$K=\dfrac{1}{2}mv^2\\\Rightarrow K=\dfrac{1}{2}2268\times 15^2\\\Rightarrow K=255150\ J$

The initial kinetic energy of the truck is 255150 J

Acceleration is given by

$a=-\dfrac{f}{m}\\\Rightarrow a=-\dfrac{700}{2268}\\\Rightarrow a=-0.30864\ m/s^2$

From equation of motion

$v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0^2-15^2}{2\times -0.30864}\\\Rightarrow s=364.50233\ m$

The stopping distance of the truck is 364.50233 m

6 0

3 years ago

In 1665 Sir Isaac Newton proposed the fundamental law of gravitation as a universal force of attraction between any two bodies.

Levart [38]

Cause of the graventation rings around earth it keeps the moon from going anywhere

6 0

4 years ago

Read 2 more answers

A runner slows down after completing works her deceleration is 0.25m/s after 5 sec she is traveling at 4m/s determine her initia

kkurt [141]

Answer:

vi = 5.25 m/s

Explanation:

We can determine the initial velocity of the runner by using the first equation of motion, as follows:

$v_f = v_i + at\\$

where,

vf = final speed of the runner = 4 m/s

vi = initial speed of the runner = ?

a = deceleration of the runner = - 0.25 m/s²

t = time taken = 5 s

Therefore,

$4\ m/s = v_i + (-0.25\ m/s^2)(5\ s)\\v_i = 4\ m/s + 1.25\ m/s\\$

vi = 5.25 m/s

5 0

3 years ago

Suppose that two objects attract each other with a gravitational force of 16 units. If the distance between the two objects is r

Yuri [45]

It would be 8 units becuase half of 16 is 8

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3 years ago

At what distance (in m) is the electrostatic force between two electrons equal to the weight of one?

Ksivusya [100]

Answer:

Explanation:

Given

Electrostatic force between two electrons is equal to weight of one electron

i.e.

$\frac{kq_1q_2}{r^2}=m_e\cdot g$

where $q_1,q_2$ are the charge of particles

$m_e=$ mass of electron

r=distance between them

$\frac{9\times 10^{9}\times 1.6\times 10^{-19}\times 1.6\times 10^{-19}}{r^2}=9.11\times 10^{-31}\times 9.8$

$r=5.08\ m$

3 0

3 years ago