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3 years ago

Can you please help me? Solve for w 8 = 4 x w

Mathematics

2 answers:

zloy xaker [14]3 years ago

8 0

Answer:

w=2

Step-by-step explanation:

$8 = 4 \times w$

Divide both sides by 4

$\frac{8}{4} = \frac{4w}{4} \\\\2=w\\\\w=2$

Daniel [21]3 years ago

3 0

Answer:

Solution for w/4=8 equation: w/4=8 We simplify the equation to the form, which is simple to understand w/4=8 Simplifying: + 0.25w=8 We move all terms containing w to the left and all other terms to the right. + 0.25w=+8 We simplify left and right side of the equation. + 0.25w=+8 We divide both sides of the equation by 0.25 to get w. w=32

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andrezito [222]

Answer:

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Step-by-step explanation:

Expand both factors and collect like term

Using Pascal' triangle with n = 6 to obtain the coefficients

1 6 15 20 15 6 1

Decreasing powers of 1 from $1^{6}$ to $1^{0}$

Increasing powers of 3x from $(3x)^{0}$ to $(3x)^{6}$

$1+3x)^{6}$

= 1. $1^{6}$ $(3x)^{0}$ + 6. $1^{5}$ $(3x)^{1}$ + 15. $1^{4}$ $(3x)^{2}$ + 20. $1^{3}$ $(3x)^{3}$ + 15.1² $(3x)^{4}$ + 6. $1^{1}$ $(3x)^{5}$ + 1. $1^{0}$ $(3x)^{6}$

= 1 + 18x + 135x² + 540x³ + 1215 $x^{4}$ + 1458 $x^{5}$ + 729 $x^{6}$

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$(1-3x)^{6}$

= 1. $1^{6}$ $(-3x)^{0}$ + 6. $1^{5}$ $(-3x)^{1}$ + 15. $1^{4}$ $(-3x)^{2}$ + 20. $1^{3}$ $(-3x)^{3}$ + 15.1² $(-3x)^{4}$ + 6. $1^{1}$ $(-3x)^{5}$ + 1. $1^{0}$ $(-3x)^{6}$

= 1 - 18x + 135x² - 540x³ + 1215 $x^{4}$ - 1458 $x^{5}$ + 729 $x^{6}$

----------------------------------------------------------------------------------

Collecting like terms from both expressions

$(1+3x)^{6}$ + $(1-3x)^{6}$

= 2 + 270x² + 2430 $x^{4}$ + 1458 $x^{6}$

----------------------------------------------------

(2)

Using Pascal's triangle with n = 5

1 5 10 10 5 1

Decreasing powers of 1 from $1^{5}$ to $1^{0}$

Increasing powers of 2x from $(2x)^{0}$ to $(2x)^{5}$

$(1+2x)^{5}$

= 1. $1^{5}$ $(2x)^{0}$ + 5. $1^{4}$ $(2x)^{1}$ + 10. $1^{3}$ $(2x)^{2}$ + 10. $1^{2}$ $(2x)^{3}$ + 5. $1^{1}$ $(2x)^{4}$ + 1. $1^{0}$ $(2x)^{5}$

= 1 + 10x + 40x² + 80x³ + 80 $x^{4}$ + 32 $x^{5}$

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3 years ago

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1. is 8
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3 years ago

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3 years ago

Resuelve las siguientes ecuaciones y luego verifica<br> A-)3x +1=7<br> B-)2a-2=1+3a

jarptica [38.1K]

Answer:

A) x=2

B) a=-3

Step-by-step explanation:

La primera ecuación dada es,

A) 3x + 1 = 7

Reste 1 de ambos lados, tenemos

3x +1-1=7-1

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Dividir por 3 (ya que 3 es un número distinto de cero) de ambos lados, tenemos

$\frac{3x}{3}=\frac {6}{3}$

$\Rightarrow x=2$

Ahora, compruebe si x = 2 es la solución correcta o no.

El lado izquierdo de la ecuación dada es 3x + 1.

Ponga x = 2, tenemos

$3\times2+1=7$

Que es igual al lado derecho de la ecuación dada.

Por tanto, x = 2 es la solución correcta.

La segunda ecuación es

B) 2a-2=1+3a

Reste 3a de ambos lados, tenemos

2a-2-3a=1+3a-3a

$\Rightarrow -a-2=1$

Suma 2 de ambos lados, tenemos

-a-2+2=1+2

$\Rightarrow -a=3$

Multiplica por -1 (como -1 es un número distinto de cero) de ambos lados, tenemos

$-a\times (-1)=3\times(-1)$

$\Rightarrow a=-3$

Ahora, verifique si a = -3 es la solución correcta o no

El lado izquierdo de la ecuación dada es 2a-2.

Ponga a = -3, tenemos

$2\times(-3)-2=-8$

El lado derecho de la ecuación dada es 1 + 3a.

Ponga a = -3, tenemos

$1+3\times(-3)=-8$ .

Aquí, al poner a = -3, el valor del lado izquierdo es igual al valor del lado derecho.

Por tanto, a = -3 es la solución correcta.

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3 years ago

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Oksi-84 [34.3K]

Hello,

2x² - 8x = 0

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2x(x - 4) = 0

2x = 0 or x - 4 = 0

x = 0 or x = 4

5 0

2 years ago