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Shkiper50 [21]
3 years ago
8

The speed of an object doubles.How does the change in the magnitude of the objects

Physics
1 answer:
IgorC [24]3 years ago
8 0

Answer:

The change in kinetic energy is twice the change in momentum

Explanation:

The momentum of an object is given by:

where

m is the mass of the object

v is its velocity

While the kinetic energy is given by

We want to check how these two quantities change when the speed of the object doubles, therefore when the new velocity is

For the momentum, we have

So, the momentum doubles.

For the kinetic energy, we have

So, the kinetic energy quadruples.

Therefore, the change in kinetic energy is twice the change in momentum.

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Nutka1998 [239]

The answers to all the research related questions are written below.

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Atom is the smallest unit of the element. Different elements have different size atoms and same element have same size atoms.

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8 0
2 years ago
Light has a frequency of about 6 x1014 Hz.
abruzzese [7]

Answer:

The visible light frequency is 400 THz to 700 THz, approximately. A THz is a Terahertz, which is a unit of frequency equal to one trillion Hertz.

4 0
2 years ago
Which element in the 18th column of the periodic table (shown below) has the largest radius?
Alex17521 [72]

Answer: Rn :)))) no explanation needed

3 0
3 years ago
Refer the attached photo
Fofino [41]

Answer:

A

Explanation:

since the wooden bat is an opaque object placed after a translucent object, light will come through the plastic sheet but will be unable to go through the bat. hence the dark shadow of the bat on a lit sheet

8 0
4 years ago
A solenoid 91.0 cm long has a radius of 1.50 cm and a winding of 1300 turns; it carries a current of 3.60 A. Calculate the magni
irinina [24]

The magnitude of the magnetic field inside the solenoid is 6.46 \times 10^{-3} \ T.

The given parameters;

  • <em>length of the solenoid, L = 91 cm = 0.91 m</em>
  • <em>radius of the solenoid, r = 1.5 cm = 0.015 m</em>
  • <em>number of turns of the solenoid, N = 1300 </em>
  • <em>current in the solenoid, I = 3.6 A</em>

The magnitude of the magnetic field inside the solenoid is calculated as;

B = \mu_0 nI\\\\B = \mu_o(\frac{ N}{L} )I\\\\

where;

\mu_o is the permeability of frees space = 4π x 10⁻⁷ T.m/A

B = (4\pi \times 10^{-7}) \times (\frac{1300}{0.91} ) \times 3.6\\\\B = 6.46 \times 10^{-3} \ T

Thus, the magnitude of the magnetic field inside the solenoid is 6.46 \times 10^{-3} \ T.

Learn more here:brainly.com/question/17137684

7 0
2 years ago
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