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3 years ago

8

The speed of an object doubles.How does the change in the magnitude of the objects

1 answer:

IgorC [24]3 years ago

8 0

Answer:

The change in kinetic energy is twice the change in momentum

Explanation:

The momentum of an object is given by:

where

m is the mass of the object

v is its velocity

While the kinetic energy is given by

We want to check how these two quantities change when the speed of the object doubles, therefore when the new velocity is

For the momentum, we have

So, the momentum doubles.

For the kinetic energy, we have

So, the kinetic energy quadruples.

Therefore, the change in kinetic energy is twice the change in momentum.

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The atmosphere of Jupiter is essentially made up of hydrogen, H2. For H2, the specific gas constant is 4157 J/(kg K). The accele

Alenkinab [10]

Answer:

h=17357.9m

Explanation:

The atmospheric pressure is just related to the weight of an arbitrary column of gas in the atmosphere above a given area. So, if you are higher in the atmosphere less gass will be over you, which means you are bearing less gas and the pressure is less.

To calculate this, you need to use the barometric formula:

$P=P_0e^{-\frac{Mg}{RT}h}$

Where R is the gas constant, M the molar mass of the gas, g the acceleration of gravity, T the temperature and h the height.

Furthermore, the specific gas constant is defined by:

$R_{H_2}=\frac{R}{M}$

Therefore yo can write the barometric formula as:

$P=P_0e^{-\frac{g}{R_{H_2}T}h}$

at the surface of the planet (h =0) the pressure is $P_0[\tex]. The pressure at the height requested is half of that:[tex]P=\frac{P_0}{2}$

applying to the previuos equation:

$\frac{P_0}{2} =P_0e^{-\frac{g}{R_{H_2}T}h}$

solving for h:

h=17357.9m

3 0

4 years ago

A box of mass 12 kg is at rest on a flat floor. The coefficient of static friction between the box and floor is 0.42. What is th

vladimir2022 [97]

As we know that friction force on box is given by

$F_s = \mu_s N$

here we know that

$N = mg$

here we have

m = 12 kg

$\mu_s = 0.42$

so now we have

$N = 12(9.8) = 117.6 N$

now we will have

$F_s = 0.42(12)(9.8)$

$F_s = 49.4 N$

so it required minimum 49 N(approx) force to move the block

5 0

4 years ago

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It takes 4.0 eV to excite an electron in a box from the ground level to the first excited level. What is the width L of the box?

AveGali [126]

To solve this problem we will use the concept related to electrons in a box which determines the energy of an electron in that state.

Mathematically this expression is given by,

$E_n= \frac{n^2h^2}{8mL^2}$

Where,

m = mass of an electron

h = Planck's constant

n = is the integer number of the eigenstate

L = Quantum well width

The change in energy must be given in state 1 and 2, therefore

$\Delta E = E_2 - E_1$

$\Delta E = \frac{2^2h^2}{8mL^2}-\frac{1^2h^2}{8mL^2}$

$\Delta E = \frac{3h^2}{8mL^2}$

Replacing we have:

$(4*1.6*10^{-19}) = \frac{3(6.626*10^{34})}{8*(9.11*10^{-31})*L^2}$

$L = 0.53nm$

Therefore the correct answer is C.

6 0

3 years ago

Here's a great everyday use of the physics described in Think about what subsequently happens to the ketchup, which is initially

balandron [24]

Answer:

Explanation:

The inertia of the ketchup will keep it from moving if it isn't too tightly adhered to the sides of the moving bottle.

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3 years ago

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Which statement is true? A) The work done to lift an object 6 meters is greater than the gravitational potential energy it gains

inna [77]

The work required to raise an object to a height is equal to the gravitational potential energy the object gains. <em>(C)</em>

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4 years ago