Question

Calculate the lithium ion (Li+) concentration for a 0.821 M Li2S solution.

Answer 1

The lithium ion[Li⁺]=1.642 M

Further explanation

Ionic compounds will dissociate into ions when dissolved in water. The strength of the dissociation depends on the strength of the electrolyte properties. The stronger it is, the more ions will dissociate

Reaction

Li₂S⇒2Li⁺+S²⁻

mol ratio Li₂S : Li⁺: S²⁻ = 1 : 2 : 1

so the lithium-ion (Li⁺) concentration :

$\tt 2\times 0.821=1.642~M$