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Alexeev081 [22]

3 years ago

8

Help me, please !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1

1 answer:

erica [24]3 years ago

3 0

Answer:

The first one is the answer

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PLEASE PLEASE PLEASE PLEASE HURRY I ONLY HAVE 59 MINUTES LEFT REEEEEE

KengaRu [80]

Answer:

The second and fourth one

Step-by-step explanation:

The open circle means more/less than or equal to and the closed circle is only more than or less than and it is greater so it goes right

3 0

3 years ago

Please help. 15 points. Show all work. Thank you.

Sergio039 [100]

The last net has all of the requirements. All you have to do then is count, which means the vertices from the hexagon all add up to 12. The rectangles are supposed to encircle it to make a closed object, which gives it eight faces, hexagons included.

8 0

3 years ago

Read 2 more answers

Please help with number 6 ASAP I will mark branlist

DerKrebs [107]

Answer:

<h2>12</h2><h2>Step-by-step explanation:</h2>

$4\sqrt{9}\\\\\mathrm{Factor\:the\:number:\:}\:9=3^2\\=4\sqrt{3^2}\\\\\mathrm{Apply\:radical\:rule}:\quad \sqrt{a^2}=a,\:\quad \:a\ge 0\\\sqrt{3^2}=3\\\\=4\times\:3\\\\=12$

5 0

3 years ago

Write 0.125 as if it was 2 to a power

Westkost [7]

Answer:

$2^{-3}$

Step-by-step explanation:

0.125 as a fraction is 125/1000 or 1/8

1 is the same as $2^{0}$ (anything to the power of 0 is 1)
8 is the same as 2³ (2 × 2 × 2 = 8)
$2^{0}$ ÷ 2³ = $2^{-3}$ (You subtract the powers: 0 - 3 = -3)

Hope this helps!

4 0

2 years ago

A machine has four components, A, B, C, and D, set up in such a manner that all four parts must work for the machine to work pro

olchik [2.2K]

Answer:

0.756

Step-by-step explanation:

It is given that a machine has four components, A, B, C, and D.

$P(A)=P(B)=0.93, P(C)=0.95,P(D)=0.92$

If these components set up in such a manner that all four parts must work for the machine to work properly.

We need to find the probability that the machine works properly. It means we have to find the value of $P(A\cap B\cap C\cap D)$ .

If two events X and Y are independent, then

$P(X\cap Y)=P(X)\times P(Y)$

Assume the probability of one part working does not depend on the functionality of any of the other parts.

$P(A\cap B\cap C\cap D)=P(A)\times P(B)\times P(C)\times P(D)$

Substitute the given values.

$P(A\cap B\cap C\cap D)=0.93\times 0.93\times 0.95\times 0.92$

$P(A\cap B\cap C\cap D)=0.7559226$

$P(A\cap B\cap C\cap D)\approx 0.756$

Therefore, the probability that the machine works properly is 0.756.

7 0

3 years ago