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3 years ago

14

Air resistance on a moving object is caused by?

1 answer:

goblinko [34]3 years ago

7 0

Answer:

Air resistance, also known as drag, is a force that is caused by air, the force acts in the opposite direction to an object moving through the air. It is where air particles hit the front of the object slowing it down. The more surface area, the more air particles hit it and the greater the resistance.

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Using this formula vf =vi+at if a vehicle starts from rest and. Accelerates forward at 4.5m/s for 8s what is the final velocity

iragen [17]

Answer: vf= 36 m/s

Explanation:

8 0

4 years ago

Which of the following is true about this lever?

zysi [14]

As we can see here the lever has two forces at two ends

1. 300 N

2. 200 N

now we need to find the Torque on the lever about the fulcrum

so we will have

1. clockwise torque due to force at right end is

$\tau_1 = d_1F_1$

$\tau_1 = 6(200) = 1200 Nm$

2. counterclockwise torque due to force at left end

$\tau_2 = d_2F_2$

$\tau_2 = 1(300) = 300 Nm$

so as per above calculations we can see that net torque on the lever is clockwise as it has more torque in clockwise direction

so <u>it will rotate clockwise</u>

6 0

3 years ago

Read 2 more answers

Can anyone help me plz

scoray [572]

Answer:

B and A

Explanation:

6 0

3 years ago

Read 2 more answers

For a person with a Near Point (NP) = 45 cm, what would be his prescription's lens power = _________ diopters A) 1.08 diopters

natita [175]

Answer:

The power of lens is 2.22 D.

Explanation:

Given that,

Distance of image v= 45 cm

We know that,

Distance of object u= ∞

Power of lens is the reciprocal of focal length.

$P=\dfrac{1}{f}$

We need to calculate the power of lens

Using formula of lens

$\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}$

Where, f = focal length

v = image distance

u = object distance

Put the value into the formula

$\dfrac{1}{f}=\dfrac{1}{45}+\dfrac{1}{\infty}$

$\dfrac{1}{f}=\dfrac{1}{0.45}+0$

$P=\dfrac{1}{f}=2.22$

Hence, The power of lens is 2.22 D.

7 0

3 years ago

Suppose that an electron and a positron collide head-on. Both have kinetic energy of 1.20 MeV and rest energy of 0.511 MeV. They

AnnZ [28]

Answer:

E = 1.711 MeV

Explanation:

From the law of the conservation of energy:

$K.E_{e}+K.E_p + E_{e}+E_{p} = 2 E$

where,

$K.E_e=K.Ep=$ the kinetic energy of positron and electron = 1.2 MeV

$E_e=E_p =$ Rest energy of the electron and the positron = 0.511 MeV

E = Energy of Photon = ?

Therefore,

$1.2\ MeV + 1.2\ MeV + 0.511\ MeV + 0.511\ MeV = 2E\\\\E = \frac{3.422\ MeV}{2}\\\\$

<u>E = 1.711 MeV</u>

3 0

3 years ago