Answer: all other conditions equal, the rate evaporation of a contained liquid will be slower than the rate of evaporation of an uncontained liquid.
Justification:
1) The rate of evaporation increases as the surface area of the liquid (relative to the whole content) increases. This is, the greater the surface is the faster the evaporation.
2) That is so because the higher the surface of the liquid the more the number of particles in the liquid that are in contact with the surrounding air and so the more the particles will escape from the liquid to the air (which is what evaporation is).
3) A liquid contained will take the form of the container, so part of the liquid wil remain below the surface, while an uncontained liquid will spread all over the surface and so pratically all the liquid is in contact witht the air surrounding it.
The correct options are these:
1. It will follow the law of conservation of mass.
2.The mass of products will be equal to the mass of the reactants.
The law of conservation of mass states that ' matter can neither be created nor destroyed. Thus, if a chemical equation is balanced, the mass of the reactant at the beginning of the reaction will be equal to the mass of the product after the reaction. This shows that the chemical reaction obeys the law of conservation of mass.
<u>Francium</u><u> </u><u>is</u><u> </u><u>less</u><u> </u><u>e</u><u>l</u><u>e</u><u>ctronegative</u><u> </u><u>than</u><u> </u><u>barium</u>
Answer: The heat of reaction (ΔHrxn) for the reaction is -164.9kJ
Explanation:
The given balanced chemical reaction is,
To calculate the enthalpy of reaction 
.
![\Delta H^o=[n_{CaCl_2}\times \Delta H_f^0_{(CaCl_2)}+n_{CO_2}\times \Delta H_f^0_{(CO_2)}+n_{H_2O}\times \Delta H_f^0_{(H_2O)}]-[n_{CaCO_3}\times \Delta H_f^0_{(CaCO_3)+n_{HCl}\times \Delta H_f^0_{(HCl)}]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo%3D%5Bn_%7BCaCl_2%7D%5Ctimes%20%5CDelta%20H_f%5E0_%7B%28CaCl_2%29%7D%2Bn_%7BCO_2%7D%5Ctimes%20%5CDelta%20H_f%5E0_%7B%28CO_2%29%7D%2Bn_%7BH_2O%7D%5Ctimes%20%5CDelta%20H_f%5E0_%7B%28H_2O%29%7D%5D-%5Bn_%7BCaCO_3%7D%5Ctimes%20%5CDelta%20H_f%5E0_%7B%28CaCO_3%29%2Bn_%7BHCl%7D%5Ctimes%20%5CDelta%20H_f%5E0_%7B%28HCl%29%7D%5D)
where,
Putting values in above equation, we get:
![\Delta H^o_{rxn}=[(1\times -877.1)+(1\times -393.51)+(1\times -285.8)]-[(1\times -1206.9)+(2\times -92.30)]=-164.9kJ](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5B%281%5Ctimes%20-877.1%29%2B%281%5Ctimes%20-393.51%29%2B%281%5Ctimes%20-285.8%29%5D-%5B%281%5Ctimes%20-1206.9%29%2B%282%5Ctimes%20-92.30%29%5D%3D-164.9kJ)
Therefore the heat of reaction (ΔHrxn) for the reaction is -164.9kJ
Answer is: there is 3,36 micrograms of iron in <span>sample of Greg's blood.
</span>m(Fe) = 42 mcg(micrograms).
V(Fe) = 1 dL = 1 dL · 100 mL/1dL.
V(Fe) = 100 mL.
Make proportion: m(Fe) : 8 mL = 42 mcg : 100 mL.
100 mL · m(Fe) = 8 mL · 42 mcg.
m(Fe) = 336 mL·mcg ÷ 100 mL.
m(Fe) = 3,36 mcg.
