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SpyIntel [72]
3 years ago
13

Calculate the LER for the rectangular wing from the previous question if the weight of the glider is 0.0500 Newton’s.

Engineering
2 answers:
Allushta [10]3 years ago
8 0

Answer: 0.2025

Explanation: I got it correct

lapo4ka [179]3 years ago
3 0

Answer:

0.2

Explanation:

Since the span and chord of the rectangular wing is missing, due to it being from the other question, permit me to improvise, or assume them. While you go ahead and substitute the ones from your question to it, as it's both basically the same method.

Let the span of the rectangular wing be 0.225 m

Let the chord of the rectangular wing be 0.045 m.

Then, the area of any rectangular chord is

A = chord * span

A = 0.045 * 0.225

A = 0.010 m²

And using the weight of the glider given to us from the question, we can find the LER for the wing.

LER = Area / weight.

LER = 0.010 / 0.05

LER = 0.2.

Therefore, using the values of the rectangular wing I adopted, and the weight of the glider given, we can see that the LER of the glider is 0.2

Please mark brainliest...

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boyakko [2]

Answer:

Finally, display the number of grapevines that will fit in the row

Explanation:

A vineyard owner is planting several new rows of grapevines, and needs to know how many grapevines to plant in each row. She has determined that after measuring the length of a future row, she can use the following formula to calculate the number of vines that will fit in the row, along with the trellis end-post assemblies that will need to be constructed at each end of the row:

V=R-2E/S

The terms in the formula are:

V is the number of grapevines that will fit in the row.

R is the length of the row, in feet.

E is the amount of space, in feet, used by an end-post assembly.

S is the space between vines, in feet.

Write a program that makes the calculation for the vineyard owner. The program should ask the user to input the following:

• The length of the row, in feet

• The amount of space used by an end-post assembly, in feet

• The amount of space between the vines, in feet

Once the input data has been entered, the program should calculate and display the number of grapevines that will fit in the row.

• Declare the variables amountSpace, vinesSpace, and grapevines of double type.

• Prompt and read the length of the row, in feet, the amount of space, in feet, and the space between vines, in feet.

• Calculate the number of grapevines that will fit in the row using the below formula:

grapvines=(rowLength-2*amountSpace)/vinesSpace;

• Finally, display the number of grapevines that will fit in the row.

8 0
3 years ago
Technician A says that a circuit with continuity reads 0 ohms. Technician B says that an open circuit reads 0 ohms. Who is corre
patriot [66]

Answer:

  A

Explanation:

An open circuit has infinite resistance, not 0. A circuit with continuity usually measures a few ohms or less, depending on the length and gauge of the wire and the condition of the connections. Often, on a general-purpose ohmmeter, the reading is very near 0 ohms.

Technician A is correct.

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Answer:

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2 years ago
(a) Consider a message signal containing frequency components at 100, 200, and 400 Hz. This signal is applied to a SSB modulator
MakcuM [25]

Answer:

Explanation:

The frequency components in the message signal are

f1 = 100Hz, f2 = 200Hz and f3 = 400Hz

When amplitude modulated with a carrier signal of frequency fc = 100kHz

Generates the following frequency components

Lower side band

100k - 100 = 99.9kHz\\\\100k - 200 = 99.8kHz\\\\100k - 400 = 99.6kHz\\\\

Carrier frequency 100kHz

Upper side band

100k + 100 = 100.1kHz\\\\100k + 200 = 100.2kHz\\\\100k + 400 = 100.4kHz

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100k, 100.1k, 100.2k\ \texttt {and}\ 100.4kHz

At the receive these are mixed (superheterodyned) with local ocillator frequency whichh is 100.02KHz, the output frequencies will be

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100k, 99.9k, 99.8k\ \ and \ \99.6kHz

At the receive these are mixed (superheterodyned) with local oscillator frequency which is 100.02KHz, and then fed to the detector whose output frequencies will be

100.02 - 99.9k = 0.12k = 120Hz\\\\100.02 - 99.8k = 0.22k = 220Hz\\\\100.02 - 99.6k = 0.42k = 420Hz

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solmaris [256]

Answer:

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