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Alex73 [517]
2 years ago
6

Ve. In what layer do weather balloons fly? Earth layers

Chemistry
1 answer:
galben [10]2 years ago
6 0

Answer:

stratosphere

Explanation:

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What has 20 electrons in 44 Mass
nadya68 [22]

It would be Calcium: Ca

6 0
3 years ago
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Can you help me with these questions?
ZanzabumX [31]
1.) C. Microwave, visible, gamma
4.) B. I’m pretty sure frequency increases from left to right and wavelength gets shorter

1.) A. Atomic bomb
2.) C. GPS
3.) A. FM radio
4.) B. Radar detector

It’s been like 2-3 years since I’ve done this stuff so I’m not entirely sure‍♀️
7 0
2 years ago
How many atoms are in a solid piece of iron that has a mass of 24.0g?
Julli [10]
Atomic mass iron ( Fe ) = 55.84 a.m.u

55.84 g ------------ 6.02x10²³ atoms
24.0 g ------------- ??

24.0 x ( 6.02x10²³) / 55.84

=> 2.58x10²³ atoms
5 0
3 years ago
A combustion analysis of 5.214 g of a compound yields 5.34 g co 2 ​ , 1.09 g h 2 ​ o, and 1.70 g n 2 ​ . if the molar mass of th
nekit [7.7K]
Answer is: C₃H₃N₃O₃.
Chemical reaction: CₓHₓNₓOₓ + O₂ → aCO₂ + x/2H₂ + x/2N₂.
m(CₐHₓNₓ) = 5,214 g.
m(CO₂) = 5,34 g.
m(H₂) = 1,09 g.
m(N₂) = 1,70 g.
n(CO₂) = n(C) =  5,34 g ÷ 44 g/mol = 0,121 mol.
n(H₂O) = 1,09 g ÷18 g/mol = 0,06 mol.
n(H) = 2 · 0,0605 mol = 0,121 mol.
n(N₂) = 1,7 g ÷ 28 g/mol = 0,0607 mol.
n(N) = 0,0607 mol · 2 = 0,121 mol.
n(C) : n(H) : n(N) = 0,121 mol : 0,121 mol : 0,121 mol /: 0,121
n(C) : n(H) : n(N) = 1 : 1 : 1.
M(CHN) = 27 g/mol.
m(O₂) = 8,13 g - 5,214 g = 2,914 g.
n(O₂) = 2,914 g ÷ 32 g/mol = 0,09 mol.
n(CₓHₓNₓOₓ) = 5,214 g ÷ 129,1 g/mol = 0,0404 mol.
n(CₓHₓNₓOₓ) : n(CO₂) = 1 : 3.


3 0
3 years ago
Read 2 more answers
Functional group and bond hybridization of vanillin
lana66690 [7]

Vanillin is the common name for 4-hydroxy-3-methoxy-benzaldehyde.

See attached figure for the structure.

Vanillin have 3 functional groups:

1) aldehyde group:  R-HC=O, in which the carbon is double bonded to oxygen

2) phenolic hydroxide group: R-OH, were the hydroxyl group is bounded to a carbon from the benzene ring

3) ether group: R-O-R, were hydrogen is bounded through sigma bonds to carbons

Now for the hybridization we have:

The carbon atoms involved in the benzene ring and the red carbon atom (from the aldehyde group) have a <u>sp²</u> hybridization because they are involved in double bonds.

The carbon atom from the methoxy group (R-O-CH₃) and the blue oxygen's have a  <u>sp³</u>  hybridization because they are involved only in single bonds.

7 0
3 years ago
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