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FromTheMoon [43]
3 years ago
5

Use the quadratic formula to solve for x. 4x2 +9x-1=0​

Mathematics
1 answer:
insens350 [35]3 years ago
5 0

Answer:

x=\frac{-9\pm\sqrt{65} }{8}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Standard Form: ax² + bx + c = 0
  • Quadratic Formula: x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}

Step-by-step explanation:

<u>Step 1: Define</u>

4x² + 9x - 1 = 0

<u>Step 2: Define variables</u>

a = 4

b = 9

c = -1

<u>Step 3: Find roots</u>

  1. Substitute:                    x=\frac{-9\pm\sqrt{9^2-4(4)(-1)} }{2(4)}
  2. Exponents:                   x=\frac{-9\pm\sqrt{81-4(4)(-1)} }{2(4)}
  3. Multiply:                        x=\frac{-9\pm\sqrt{81-16} }{8}
  4. Subtract:                       x=\frac{-9\pm\sqrt{65} }{8}
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To determine the number of possible solutions for a triangle with A = 113° , a = 15, and b = 8, we're going to use the law of sines which states that: "<em>When we divide side a by the sine of angle A  it is equal to side b divided by the sine of angle B,  and also equal to side c divided by the sine of angle C</em>".

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