3 years ago

¿En cuáles está presente la química?

Chemistry

1 answer:

Step2247 [10]3 years ago

8 0

Answer:

Explanation:

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Kryger [21]

Its b im pretty sure

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3 years ago

Calculate no. Of moles in 329g of H2so4

Anestetic [448]

Mol= mass (grams) /Mr
Mr of Sulfuric Acid (H2SO4): 98
mol= 329/98
=3.36 moles

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3 years ago

A sample of a substance has a mass of 4.2 grams and a volume of 6 milliliters

allsm [11]

Answer:

Density of the substance is 0.7

Explanation:

4.2/6 = 0.7

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Why is melting an ice cube a reversible physical change?

Dmitriy789 [7]

Answer:

Because you can freeze the water you melted back into a ice cube.

Explanation:

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Consider the following equilibrium: H2CO3+H2O = H3O+HCO3^-1. What is the correct equilibrium expression?

mylen [45]

Equilibrium expression is $Keq = \frac{[H3O+][HCO3^-]}{[H2CO3]}\\$

<u>Explanation:</u>

Equilibrium expression is denoted by Keq.

Keq is the equilibrium constant that is defined as the ratio of concentration of products to the concentration of reactants each raised to the power its stoichiometric coefficients.

Example -

aA + bB = cC + dD

So, Keq = conc of product/ conc of reactant

$Keq = \frac{[C]^c [D]^d}{[A]^a [B]^b}$

So from the equation, H₂CO₃+H₂O = H₃O+HCO₃⁻¹

$Keq = \frac{[H3O^+]^1 [HCO3^-]^1}{[H2CO3]^1 [H2O]^1}$

The concentration of pure solid and liquid is considered as 1. Therefore, concentration of H2O is 1.

Thus,

$Keq = \frac{[H3O+][HCO3^-]}{[H2CO3]}\\$

Therefore, Equilibrium expression is $Keq = \frac{[H3O+][HCO3^-]}{[H2CO3]}\\$

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3 years ago