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3 years ago

Which of the following are held together by nonpolar convalent bonds?

Chemistry

1 answer:

Olin [163]3 years ago

6 0

A. Atoms of chlorine (Cl)

Explanation:

The atoms of chlorine are held together by non-polar covalent bonds.

Covalent bonds are formed between two or more atoms having zero or very small electronegativity difference.
For homonuclear molecules where the two bonding atom are of the same kind, the electronegativity difference is zero.
This covalent bond type is called non-polar covalent bond.
In this bond type, there is equal sharing of the electron pair between the atoms and there is no electrostatic charge on the molecule.

Learn more:

Covalent bond brainly.com/question/5258547

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Find the volume of a gas at STP, if its volume is 80.0 mL at 109 kPa and -12.5°C.

exis [7]

Answer:

= 913.84 mL

Explanation:

Using the combined gas laws

P1V1/T1 = P2V2/T2

At standard temperature and pressure. the pressure is 10 kPa, while the temperature is 273 K.

V1 = 80.0 mL

P1 = 109 kPa

T1 = -12.5 + 273 = 260.5 K

P2 = 10 kPa

V2 = ?

T2 = 273 K

Therefore;

V2 = P1V1T2/P2T1

= (109 kPa × 80 mL × 273 K)/(10 kPa× 260.5 K)

= 913.84 mL

5 0

3 years ago

Read 2 more answers

A 1M solution is made of each item in a pair. When would this combination create a buffer? Chose the pairs below that you could

monitta

Answer:

b. HCOOH/ NaHCOO.

Explanation:

A buffer system may be formed in one of two forms:

A weak acid with its conjugate base.

A weak base with its conjugate acid.

Chose the pairs below that you could use to make a buffered solution.

a. HCI/NaOH. NO. HCl is a strong acid and NaOH is a strong base.

b. HCOOH/ NaHCOO. YES. HCOOH is a weak acid and HCOO⁻ (coming from NaHCOO) is its conjugate base.

c. HNO₂/H₂SO₃. NO. Both are acids and they are unrelated to each other.

d. NaNO₃/ HNO₃. NO. HNO₃ is a strong acid.

7 0

2 years ago

In what type of reaction or process does heat flow into the system

SCORPION-xisa [38]

Answer: The correct answer is: " endothermic . "

______________________________________

Note: Heat flows into [heat may be absorbed within] an "endothermic" reaction or system

To the contrary, heat flows out  [heat may exit from or may be released from] an "exothermic" reaction or process.

Hint: Think of the "prefixes" of: "endothermic" and "exothermic" :

_____________________________________

1) endo- = "within" (as in "endothermic" —heat tends to be absorbed/"within"/"released within"/released within"/into" ;

2) exo- = " outwards"/"exit" (as in "exothermic") —heat tends to '"exit"/leave/escape from/"be released out of/form".

_____________________________________

Hope this is helpful to you!

Best wishes to you in your academic pursuits

—and within the "Brainly" community"!

_____________________________________

5 0

3 years ago

When one form of energy is converted to another form in any physical or chemical change, energy input alwasy equals energy outpu

aliya0001 [1]

In the context of chemistry, yes. Energy input is always equal to the energy output.

5 0

2 years ago

What is the entropy change of the surroundings

KiRa [710]

Answer: The entropy change of the surroundings will be -17.7 J/K mol.

Explanation: The enthalpy of vapourization for 1 mole of acetone is 31.3 kJ/mol

Amount of Acetone given = 10.8 g

Number of moles is calculated by using the formula:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of acetone = 58 g/mol

Number of moles = $\frac{10.8}{58}=0.1862moles$

If 1 mole of acetone has 32.3 kJ/mol of enthalpy, then

0.1862 moles will have = $\frac{32.3}{1}\times 0.1862=5.828kJ/mol$

To calculate the entropy change for the system, we use the formula:

$\Delta S_{sys}=\frac{\Delta H_{vap}}{T(\text{ in K)}}$

Temperature = 56.2°C = (273 + 56.2)K = 329.2K

Putting values in above equation, we get

$\Delta S_{sys}=\frac{5.828}{329.2}=0.0177kJ/Kmol=17.7J/Kmol$ (Conversion Factor: 1 kJ = 1000J)

At Boiling point, the liquid phase and gaseous phase of acetone are in equilibrium. Hence,

$\Delta S_{system}+\Delta S_{surrounding}=0$

$\Delta S_{surrouding}=-\Delta S_{system}=-17.7J/Kmol$

5 0

3 years ago