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2 years ago

Which of the following are held together by nonpolar convalent bonds?

Chemistry

1 answer:

Olin [163]2 years ago

6 0

A. Atoms of chlorine (Cl)

Explanation:

The atoms of chlorine are held together by non-polar covalent bonds.

Covalent bonds are formed between two or more atoms having zero or very small electronegativity difference.
For homonuclear molecules where the two bonding atom are of the same kind, the electronegativity difference is zero.
This covalent bond type is called non-polar covalent bond.
In this bond type, there is equal sharing of the electron pair between the atoms and there is no electrostatic charge on the molecule.

Learn more:

Covalent bond brainly.com/question/5258547

#learnwithBrainly

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A uranium atom has 92 protons in its nucleus. how many electrons does it have?

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In a balanced, non-charged atom, the number of protons (positive charge) is equal to the number of electrons (negative charge)

So there are 92 electrons

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2 years ago

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3mL of cyclohexanol (density = 0.9624 g/mL, Molecular weight = 100.158 g/mol) reacts with excess sulfuric acid to produce cycloh

TiliK225 [7]

Answer:

$n_{C_6H_{10}}=0.03molC_6H_{10}$

Explanation:

Hello,

In this case the undergoing chemical reaction is shown on the attached picture whereas cyclohexanol is converted into cyclohexene and water by the dehydrating effect of the sulfuric acid. Thus, for the starting 3 mL of cyclohexanol, the following stoichiometric proportional factor is applied in order to find the theoretical yield of cyclohexene in moles:

$n_{C_6H_{10}}=3mLC_6H_{12}O*\frac{0.9624gC_6H_{12}O}{1mLC_6H_{12}O}*\frac{1molC_6H_{12}O}{100.158gC_6H_{12}O}*\frac{1molC_6H_{10}}{1molC_6H_{12}O} \\n_{C_6H_{10}}=0.03molC_6H_{10}$

Besides, the mass could be computed as well by using the molar mass of cyclohexene:

$m_{C_6H_{10}}=0.03molC_6H_{10}*\frac{82.143gC_6H_{10}}{1molC_6H_{10}} \\\\m_{C_6H_{10}}=2.4gC_6H_{10}$

Even thought, the volume could be also computed by using its density:

$V_{C_6H_{10}}=2.4gC_6H_{10}*\frac{1mLC_6H_{10}}{0.811gC_6H_{10}} \\V_{C_6H_{10}}=3mLC_6H_{10}$

Best regards.

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