Answer:
a coil rotating in a magnetic field to change its flux
Answer:
17.3 m
Explanation:
Given that,
Mass of a hammer is 0.58 kg
Velocity with which the hammer slides is 6.69 m/s at constant speed.
The roof makes an angle of 18 ◦ with the horizontal, and its lowest point is 18.2 m from the ground. We need to find the horizontal distance traveled by the hammer between the time is leaves the roof of the house and the time it hits the ground. Firstly, we will find the time taken by the hammer when it reaches ground in vertical direction.
![y=y_0+v_ot +\dfrac{1}{2}gt^2](https://tex.z-dn.net/?f=y%3Dy_0%2Bv_ot%20%2B%5Cdfrac%7B1%7D%7B2%7Dgt%5E2)
Putting all the values,
![0=18.2+6.69t-\dfrac{1}{2}\times 9.8t^2\\\\-4.9t^2+6.69t+18.2=0\\\\t=\dfrac{-6.69+\sqrt{6.69^{2}-4\cdot-4.9\cdot18.2}}{2\cdot-4.9}, \dfrac{-6.69-\sqrt{6.69^{2}-4\cdot-4.9\cdot18.2}}{2\cdot-4.9}\\\\t=-1.36\ s\ \text{and}\ t=2.72\ s](https://tex.z-dn.net/?f=0%3D18.2%2B6.69t-%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%209.8t%5E2%5C%5C%5C%5C-4.9t%5E2%2B6.69t%2B18.2%3D0%5C%5C%5C%5Ct%3D%5Cdfrac%7B-6.69%2B%5Csqrt%7B6.69%5E%7B2%7D-4%5Ccdot-4.9%5Ccdot18.2%7D%7D%7B2%5Ccdot-4.9%7D%2C%20%5Cdfrac%7B-6.69-%5Csqrt%7B6.69%5E%7B2%7D-4%5Ccdot-4.9%5Ccdot18.2%7D%7D%7B2%5Ccdot-4.9%7D%5C%5C%5C%5Ct%3D-1.36%5C%20s%5C%20%5Ctext%7Band%7D%5C%20t%3D2.72%5C%20s)
Neglecting negative value,
To find horizontal distance, multiply 2.72 s with the horizontal component of velocity.
![d=2.72\times 6.69\times \cos(18)\\\\d=17.3\ m](https://tex.z-dn.net/?f=d%3D2.72%5Ctimes%206.69%5Ctimes%20%5Ccos%2818%29%5C%5C%5C%5Cd%3D17.3%5C%20m)
Natural Frequency
Hope that helped!
Answer:
3.25 seconds
Explanation:
It is given that,
A person throws a baseball from height of 7 feet with an initial vertical velocity of 50 feet per second. The equation for his motion is as follows :
![h=-16t^2+vt+s](https://tex.z-dn.net/?f=h%3D-16t%5E2%2Bvt%2Bs)
Where
s is the height in feet
For the given condition, the equation becomes:
![h=-16t^2+50t+7](https://tex.z-dn.net/?f=h%3D-16t%5E2%2B50t%2B7)
When it hits the ground, h = 0
i.e.
![-16t^2+50t+7=0](https://tex.z-dn.net/?f=-16t%5E2%2B50t%2B7%3D0)
It is a quadratic equation, we find the value of t,
t = 3.25 seconds and t = -0.134 s
Neglecting negative value
Hence, for 3.25 seconds the baseball is in the air before it hits the ground.
![▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪](https://tex.z-dn.net/?f=%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%20%20%7B%5Chuge%5Cmathfrak%7BAnswer%7D%7D%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA%E2%96%AA)
According to above question ~
Let's find the charge (q) by using formula ~
Hence, 12 coulombs of charge flow past any point in the wire in 3 seconds