Answer:
Hello my friend! The correct answer is "The process shown in the image can best be described as a rapid chemical reaction where gas is released"
Explanation:
Most antacid products uses Sodium bicarbonate (NaHCO3). When placed in water, NaHCO3 reacts with acids very rapidly, releasing CO2, according to the chemical reaction below:
NaHCO3 + HCl → NaCl + H2O + CO2
Answer : The mass of reactant 
remain would be, 0.20 grams.
Solution : Given,
Moles of = 0.40 mol
Moles of 
= 0.15 mol
Molar mass of = 2 g/mole
First we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
From the balanced reaction we conclude that
As, 1 mole of react with 2 mole of
So, 0.15 moles of react with 
moles of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.
The moles of reactant remain = 0.40 - 0.30 = 0.10 mole
Now we have to calculate the mass of reactant remain.
Therefore, the mass of reactant remain would be, 0.20 grams.
You have to use the combined gas law (P₁V₁/T₁=P₂V₂/T₂) and solve for P₂ to get P₂=P₁V₁T₂/T₁V₂.
You need to convert all of the temperature values into terms of Kelvin so -50°C turns into 223K and 102°C turns to 375K. After you make that conversion you can just plug in all of the values into the idea gas law and you should get P₂=228.5kpa.
I hope this helps. Let me know if anything is unclear.
Answer: The last layer
Explanation: If nothing has affected the layers we can answer this accordingly to relative dating. The older rocks should be on the bottom while the younger rocks should be on the top.
Answer:−329.4 calorie
Explanation:Heat released by metal = q=m_mc_m(T_2-T1)q=m
m
c
m
(T
2
−T1)
m_m=50\ g\\c_m=0.108\ cal\ g^{-1}\ \degree C^{-1}\\q=50\times0.108(17-78)=-329.4\ caloriem
m
=50 g
c
m
=0.108 cal g
−1
°C
−1
q=50×0.108(17−78)=−329.4 calorie
Here minus sign indicate that heat is released
