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krok68 [10]
2 years ago
6

How much of the excess reagant in Problem 1 is left over?

Chemistry
2 answers:
Mariana [72]2 years ago
8 0
I,hfilfhhfliegfasffjaso
As
Naddik [55]2 years ago
5 0

Answer:

4 Al + 3 O2 → 2 Al2O3

(10.0 g Al) / (26.98154 g Al/mol) = 0.37062 mol Al

(19.0 g O2) / (31.99886 g O2/mol) = 0.59377 mol O2

0.37062 mole of Al would react completely with 0.37062 x (3/4) = 0.277965 mole of O2, but there is more O2 present than that, so O2 is in excess.

((0.59377 mol O2 initially) - (0.277965 mol O2 reacted)) x (31.99886 g O2/mol) =

10.1 g O2 left over

Explanation:

i really hope this is what you were looking for <3 :)

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What is the purpose of a salt bridge?
ikadub [295]

Answer: The purpose of a salt bridge is not to move electrons from the electrolyte, rather it's to maintain charge balance because the electrons are moving from one-half cell to the other. The electrons flow from the anode to the cathode.

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6 0
3 years ago
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How much time would it take for 12000 atoms of nitrogen-13 (half-life is 7.13 s) to decay to 750 atoms?
Rainbow [258]
<h3>Answer:</h3>

28.52 seconds

<h3>Explanation:</h3>

Initial number of atoms of Nitrogen 12,000 atoms

Half-life = 7.13

Number of atoms after decay = 750 atoms

We are required to determine the time taken for the decay.

Note that half life is the time taken for a radioactive isotope to decay to a half of its original amount.

Using the formula;

Remaining amount = Initial amount × (1/2)^n , where n is the number of half lives

In our case;

750 atoms = 12,000 atoms × (1/2)^n

0.0625 = 0.5^n

n = log 0.0625 ÷ log 0.5

n = 4

But, 1 half life =7.13 seconds

Therefore;

Time taken = 7.13 seconds × 4

                  = 28.52 seconds

Therefore, the time taken for 12,000 atoms of nitrogen to decay to 750 atoms is 28.52 seconds

8 0
3 years ago
The reactant concentration in a first-order reaction was 8.10×10−2 M M after 15.0 s s and 1.80×10−3 M M after 90.0 s s . What is
kipiarov [429]

Answer:

The answer to the question is

The rate constant for the reaction is 1.056×10⁻³ M/s

Explanation:

To solve the question, e note that

For a zero order reaction, the rate law is given by

[A] = -k×t + [A]₀

This can be represented by the linear equation y = mx + c

Such that y = [A], m which is the gradient is = -k, and the intercept c = [A]₀

Therefore the rate constant k which is the gradient is given by

Gradient = \frac{[A]_{2} - [A]_{1}  }{t_{2} - t_{1}  }  where [A]₁ = 8.10×10⁻² M and [A]₂ = 1.80×10⁻³ M

= \frac{1.80*10^{-3} M- 8.10*10^{-2} M}{90 s - 15 s} = -0.001056 M/s = -1.056×10⁻³ M/s

Threfore k = 1.056×10⁻³ M/s

3 0
3 years ago
Water is a pure substance. Which of the following is true about water? (4 points) Its compounds can only be physically separated
jonny [76]

Answer:

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Explanation:

7 0
3 years ago
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