A site in Pennsylvania receives a total annual deposition of 2.688 g/mof sulfate from fertilizer and acid rain. The ratio by mas
1 answer:
According to the statement
2.12 x 10^4 lbs pounds of CaCO₃ are needed to neutralize this acid
<h3>What is neutralization?</h3>A chemical reaction in which an acid and a base react quantitatively with each other is known as neutralization or neutralization. In a water reaction, neutralization ensures that there is no excess of hydrogen or hydroxide ions in the solution.
<h3>According to the given information:</h3>The equation of the neutralization reaction between H2SO4 and CaCO3.
CaCO3 + H2SO4 → CaSO4 + H2CO3
H2CO3 dissociate to water and carbon dioxide.
CaCO3 + H2SO4 → CaSO4 + H2O + CO2
Now solving for the mass of CaCO3 needed to neutralize the acid.
mass of CaCO3 = 9460 Kg H2SO4 ×
= 21284.56606
mass of CaCO3 = 2.12 x 10^4 lbs
2.12 x 10^4 lbs pounds of CaCO₃ are needed to neutralize this acid.
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Answer:
<h2>0.02 moles </h2>Explanation:
To find the number of moles in a substance given it's number of entities we use the formula
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
We have
We have the final answer as
<h3>0.02 moles</h3>Hope this helps you