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3 years ago

2. If you have 8.08 g of hydrogen, how many grams of ammonia will your produce?

Chemistry

1 answer:

Nikolay [14]3 years ago

7 0

answer: Stoichiometry is a big word for a process that chemist’s use to calculate

amounts in reactions. It makes use of the coefficient ratio set up by balanced

reaction equations to make connections between the reactants and products

in reactions.

 Stoichiometry calculates the quantities of reactants and products in a

chemical reaction. The equation must be balanced!

 Questions that deal with amounts in reactions are examples of reaction

stoichiometry. We already have the tools necessary to solve this question.

We just need to learn a new way to apply skills such as writing chemical

formulas, calculating formula masses, and converting from mass to moles,

particles to moles, and volume of gases to moles.

 Mole to Mole Conversions- you must have the Mole Ratio.

Illustration:

Let’s use an analogy that we can understand to begin to understand the process.

The KEY to any mole conversion is the ratio of coefficients in the reaction

equation. Say I want to make a bacon double cheeseburger. Let’s get our recipe

together.

1 hamburger bun + 2 hamburger patties + 2 slices of cheese + 4 strips of bacon →

1 bacon double cheeseburger

Based on this recipe:

1) If I have five bacon double cheeseburgers:

a. How many hamburger buns did you use? → 5 hamburger bun

b. How many hamburger patties did you use? → 10 hamburger patties

c. How many slices of cheese did you use? → 10 slices of cheese

d. How many strips of bacon did you use? → 20 strips of bacon

2) How many bacon double cheeseburgers can you make if you start with:

a. 2 buns, 4 patties, 4 slices of cheese, 8 strips of bacon

2 bacon double cheese burgers

b. 1 dozen buns, 2 dozen patties, 2 dozen slices of cheese, 4 dozen strips of bacon

1 dozen bacon double cheese burgers

You might be interested in

Give the name and formula of the compound formed from the following elements: a) Sodium and nitrogen b) Oxygen and strontium c)

elena-s [515]

Answer: a) Sodium and nitrogen : $NaN_3$ : sodium nitride.

b) Oxygen and strontium : $SrO$ : strontium oxide.

c) Aluminum and chlorine : $AlCl_3$ : aluminium chloride.

d) Cesium and bromine : $CsBr$ : cesium bromide.

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

a) Sodium and nitrogen : Here sodium is having an oxidation state of +1 called as $Na^{+}$ cation and nitrogen forms an anion $N^{3-}$ with oxidation state of -3. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $NaN_3$ named as sodium nitride.

b) Oxygen and strontium : Here strontium is having an oxidation state of +2 called as $Sr^{+}$ cation and oxygen forms an anion $O^{2-}$ with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $SrO$ named as strontium oxide.

c) Aluminum and chlorine : Here aluminium is having an oxidation state of +3 called as $Al^{3+}$ cation and chlorine forms an anion $Cl^{-}$ with oxidation state of -1. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $AlCl_3$ named as aluminium chloride.

d) Cesium and bromine : Here cesium is having an oxidation state of +1 called as $Cs^{+}$ cation and bromine forms an anion $Br^{-}$ with oxidation state of -1. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $CsBr$ named as cesium bromide.

7 0

3 years ago

A 3.96x10^-24 M solution of compound A exhibited an absorbance of 0.624 at 238 nm in a 1.000-cm cuvet; a blank solution containi

viktelen [127]

Actual question from source:-

A 3.96x10-4 M solution of compound A exhibited an absorbance of 0.624 at 238 nm in a 1.000 cm cuvette. A blank had an absorbance of 0.029. The absorbance of an unknown solution of compound A was 0.375. Find the concentration of A in the unknown.

Answer:

Molar absorptivity of compound A = $1502.53\ {Ms}^{-1}$

Explanation:

According to the Lambert's Beer law:-

$A=\epsilon l c$

Where, A is the absorbance

l is the path length

$\epsilon$ is the molar absorptivity

c is the concentration.

Given that:-

c = $3.96\times 10^{-4}\ M$

Path length = 1.000 cm

Absorbance observed = 0.624

Absorbance blank = 0.029

A = 0.624 - 0.029 = 0.595

So, applying the values in the Lambert Beer's law as shown below:-

$0.595=\epsilon\times 1.000\ cm\times 3.96\times 10^{-4}\ M$

$\epsilon=\frac{0.595}{3.96\times 10^{-4}}\ {Ms}^{-1}=1502.53\ {Ms}^{-1}$

<u>Molar absorptivity of compound A = $1502.53\ {Ms}^{-1}$ </u>

4 0

4 years ago

Hello how do I solve data for plotting graphs?

OverLord2011 [107]

You could solve it by analyzing the points by graphing them on a coordinate plane

4 0

3 years ago

How would you convert 500cc of 2M H2so4 in g/l and normality?

Ann [662]

Concentration :

196 g/L and 4 N

<h3> </h3><h3>Further explanation</h3>

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

500 cc of 2M H₂SO₄

V = 500 cc = 0.5 L

mol H₂SO₄

$\tt mol=M\times V=2\times 0.5=1$

mass H₂SO₄ (MW = 98 g/mol)

$\tt mass=mol\times MW=1\times 98=98~g$

concentration in g/L :

$\tt \dfrac{98}{0.5}=196~g/L$

concentration in normality

Relationship between normality and molarity

N = M x n (n=valence , amount of H⁺ or OH⁻)

so :

$\tt N=2\times 2(n=2~for~H_2SO_4\rightarrow 2H^+)\\\\N=4$

6 0

3 years ago

If 448.85 mg of KOH is dissolved in 400 ml of water, what will be the pH of the solution?

emmasim [6.3K]

I have provided the steps and solution within the attachment. The pH of the solution would be 12.30, this indicates that the solution is basic, as a higher value of pH indicates presence of more hydroxide ions and less of hydrogen ions in the solution.

8 0

4 years ago