<span>Consider a angle â BAC and the point D on its defector
Assume that DB is perpendicular to AB and DC is perpendicular to AC.
Lets prove DB and DC are congruent (that is point D is equidistant from sides of an angle â BAC
Proof
Consider triangles ΔADB and ΔADC
Both are right angle, â ABD= â ACD=90 degree
They have congruent acute angle â BAD and â CAD( since AD is angle bisector)
They share hypotenuse AD
therefore these right angle are congruent by two angle and sides and, therefore, their sides DB and DC are congruent too, as luing across congruent angles</span>
The correct answer is D because there is one area that is a cluster (bundle of dots in one area) and one outlier (away from all the other points; irrelevant).
Answer:
f(x) + 2.
Step-by-step explanation:
Example:
If we have say f(x) = x + 1 then 2 units will be added to f(x) when it is moved up 2 units.
So the equation of this line will be f(x) + 2 which in this example is
x + 1+ 2.
The new function is x + 3.
Answer:
2
Step-by-step explanation:
Rise / Run
= 4/2
= 2
Answer:
hhjbvft
Step-by-step explanation:
jojo giving kbjvuvuvvuvugubibbibiogg
