The Metabolic power,If we assume that lowering his body has no energetic cost is 667 J/min
The Metabolic power, If lowering of his body needs half of the energy is 1000J/min
<u>Explanation:</u>
<u>1.If we assume that lowering his body has no energetic cost:</u>
<u>Metabolic energy in 5 minutes</u>
= Increase in potential energy for 150 pushups
= (89 kg) × (25/100 m) × 150
= 3337.5 J
<u>Metabolic power</u>
= (3375.5 J) / (5 min)
= 667 J/min
The Metabolic power,If we assume that lowering his body has no energetic cost is 667 J/min
<u>2.If lowering of his body needs half of the energy what it costs to raise it.</u>
<u>Metabolic power</u>
= (667 J/min) × [1 + (1/2)]
= 1000 J/min
The Metabolic power, If lowering of his body needs half of the energy is 1000J/min
Answer:
40 J
Explanation:
= 4 C
= 2 C
= 20 J
The potential energy is directly proportional to the charge of the particle
The potential energy expected is 40 J
True hope this helps, <span>Nictheuse !</span>
A. 131 V
I got it right on the quiz
Velocidad angular = (angulo total) / (tiempo total)
Velocidad angular = (1080 grados) / (20 segundos)
Velocidad angular = (1080/20) g/s
Velocidad angular = 54 g/s
Pero 180 grados = π radianes
V.A. = (54 g/s) x (π rad / 180 g)
V.A. = (54π gr-rad / 180 seg-gr)
<em>V.A. = 0.3π rad/seg</em>
V.A. = aproximadamente 0.942 rad/seg
