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Jet001 [13]
2 years ago
5

HELP ME

Physics
1 answer:
sergij07 [2.7K]2 years ago
6 0

Answer:

13,308 MAYBE IF IT ISN'T IM SO SORRY

Explanation:

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Answer:

The value of the distance is \bf{14.52~cm}.

Explanation:

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The velocity of the particle will be maximum when the particle will cross its equilibrium position, i.e., x = 0.

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\dfrac{v}{v_{m}} = \dfrac{\sqrt{A^{2} - x^{2}}}{A}~~~~~~~~~~~~~~~~~~~~~~~~~~~(3)

Given, v = 0.25 v_{m} and A = 15~cm. Substitute these values in equation (3).

&& \dfrac{1}{4} = \dfrac{\sqrt{15^{2} - x^{2}}}{15}\\&or,& A = 14.52~cm

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