1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
scoray [572]
3 years ago
6

The density of a gaseous compound is 1.623 g/l at stp determine the molar mass of the compound

Chemistry
1 answer:
victus00 [196]3 years ago
4 0
<span>The molar mass of the compound is 36.355 g/mol. This is calculated by knowing that 1 mol of gas fills 22.4 L of volume, so 1.623 g/L = X g/mol * 1/22.4 mol/L -> 1.623 g/L * 22.4 L/mol = X g/mol -> 36.355 g/mol = X g/mol</span>
You might be interested in
Katrina tried to take pictures with her cell phone but discovered that its battery was dead. What happened to the battery?
Aleks04 [339]
C. All the energy stored in the battery had been transformed.
4 0
2 years ago
Read 2 more answers
If the same amount of heat is added to 5.00 g samples of each of the metals below, which metal will experience the smallest temp
Y_Kistochka [10]

Answer: -

Lower the specific heat capacity of the metal, more the amount of heat would be required to raise the temperature to the same extent.

So for the same amount of heat added to 5.00 g samples of metals, the metal with the lowest specific heat capacity would experience the smallest temperature change.

For example, if the elements are Al, Au ,Cu and Fe, then Au would experience the smallest temperature change due to least specific heat capacity.

5 0
3 years ago
At 19 °C, the vapor pressure of pure ethanol is 40.0 mmHg.<br> What is the pressure in atm?<br> atm
m_a_m_a [10]

Answer:

0.05263158 atm

Explanation: mmHg to Atmosphere Conversion Example. Task: Convert 975 mmHg to atmospheres (show work) Formula: mmHg ÷ 760 = atm Calculations: 975 mmHg ÷ 760 = 1.28289474 atm Result: 975 mmHg is equal to 1.28289474 atm. This is an example for how i got the answer.

5 0
2 years ago
Butane (C4H10) has a heat of vaporization of 22.44 kJ/mol and a normal boiling point of -0.4 ∘C. A 250 mL sealed flask contains
erastova [34]

Given that:

  • The heat of vaporization = 22.44 kJ/mol = 22440 J/mol
  • normal boiling point which is the initial temperature = 0.4° C = (273 + (-0.4))K  = 272.6 K
  • volume  = 250 mL = 0.250 L
  • Mass of butane = 0.8 g
  • the final temperature = -22° C = (273 + (-22)) K = 251 K

The first step is to determine the vapor pressure at the final temperature of 251K by using the Clausius-Clapeyron equation. This is following by using the ideal gas equation to determine the numbers of moles of butane gas. After that, the mass of butane present in the liquid is determined by using the relation for the number of moles.

Using Clausius-Clapeyron Equation:

\mathbf{In (\dfrac{P_2}{P_1} )= -\dfrac{\Delta H_{vap}}{R}(\dfrac{1}{T_2} - \dfrac{1}{T_1})}

where;

P1 and P2 correspond to the temperature at T1 and T2.

∴

replacing the values into the given equation, we have;

\mathbf{In \dfrac{P_2}{1\  atm} = -\dfrac{22440 \ J/mol}{8.314 \ J/mol.K}(\dfrac{1}{251 \ K} - \dfrac{1}{272.6 \ K})}

\mathbf{In \dfrac{P_2}{1\  atm} =-(0.852053785)}

\mathbf{P_2=0.427 \ atm}

As such, at -22° C; the vapor pressure = 0.427 atm

Now, using the ideal gas equation:

PV = nRT

where:

  • P = Pressure
  • V = volume
  • n = number of moles of butane
  • R = universal gas constant
  • T = temperature

∴

Making (n) the subject of the formula:

\mathbf{n = \dfrac{PV}{RT}}

\mathbf{n = \dfrac{0.427 atm \times 0.250 L}{(0.08206 \ L.atm/k.mol) \times 251}}

\mathbf{n =0.00518 mol}

We all know that the standard molecular weight of butane = 58.12 g/mol

∴

Using the relation for the number of moles which is:

\mathbf{number \  of \  moles = \dfrac{mass}{molar mass}}

mass = 0.00518 mole × 58.12 g/mol

mass = 0.301 g

∴

The mass of butane in the flask = 0.301 g

But the mass of the butane present as a liquid in the flask is

= 0.8 g - 0.301 g

= 0.499 g

In conclusion, the mass of the butane present as a liquid in the flask is 0.499 g

Learn more about vapourization here:

brainly.com/question/17039550?referrer=searchResults

7 0
3 years ago
Wind eroding rocks. Is it a chemical or physical change ?
stellarik [79]
This is a Physical change. No chemistry involved.
7 0
3 years ago
Read 2 more answers
Other questions:
  • How many covalent bonds are in a nitrogen molecule?
    10·1 answer
  • Which regions on the periodic table can adopt positive and negative oxidation numbers?
    12·1 answer
  • 2. An electric heating element is connected to a 110 V circuit and a current of 3.2 A is flowing though the element. How much en
    11·2 answers
  • What would be the products for the reaction Br2 + KI →? (Just identify the correct products for the reaction. You do not need to
    6·1 answer
  • 1. A student collected the following data for a fixed volume of gas: Temperature (⁰C) Pressure (mm of Hg) 10 726 20 750 40 800 7
    15·1 answer
  • Using the excerpt from the periodic table, which statement MOST accurately explains the chemical behavior of a pair of elements?
    9·2 answers
  • Which statement is correct regarding the rate of the reaction below? 3A + B yields 4X + 2Y
    8·1 answer
  • Explain why phosphoric acid is needed for the battery to operate
    10·1 answer
  • Which way would CCI2F2 orient in an electric field?
    12·1 answer
  • PLEASE HELP I DONT WANT TO FAIL!! ):
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!