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3 years ago

The density of a gaseous compound is 1.623 g/l at stp determine the molar mass of the compound

1 answer:

4 0

The molar mass of the compound is 36.355 g/mol. This is calculated by knowing that 1 mol of gas fills 22.4 L of volume, so 1.623 g/L = X g/mol * 1/22.4 mol/L -> 1.623 g/L * 22.4 L/mol = X g/mol -> 36.355 g/mol = X g/mol

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2 moles of substance A contains 12.04 × 1023 atoms.

professor190 [17]

Answer:

2 moles of Substance B

Explanation:

Because 1 mole of any substance contains 6.02× 10²³ particles either atoms, molecules, ions or even electron(Avogardo Constant)

Therefore 12.04 × 10²³/ 6.02× 10²³ = 2 mole of Substance B

7 0

2 years ago

It has been proven that North America is moving west about 2 cm per year. How many kilometers wouldn’t move in 5000 years

Viefleur [7K]

0.1 km

2cm/year * 5000 yrs = 10000 cm

1cm= .01 m

1km = 1000 m

so the answer is 0.1 km

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3 years ago

What is the molality of a solution if 100.0 g of glucose (C&Hi20e) were dissolved into 750. mL of water?

hodyreva [135]

Answer: The molality of solution is 0.740 m.

Explanation:

To calculate the mass of solvent (water), we use the equation:

$Density=\frac{Mass}{Volume}$

Volume of water = 750 mL

Density of water = 1 g/mL

Putting values in above equation, we get:

$1g/mL=\frac{\text{Mass of water}}{750mL}\\\\\text{Mass of water}=750g$

To calculate the molality of solution, we use the equation:

$Molarity=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}$

Where,

$m_{solute}$ = Given mass of solute $(C_6H_{12}O_6)$ = 100.0 g

$M_{solute}$ = Molar mass of solute $(C_6H_{12}O_6)$ = 180 g/mol

$W_{solvent}$ = Mass of solvent (water) = 750 g

Putting values in above equation, we get:

$\text{Molality of }C_6H_{12}O_6=\frac{100\times 1000}{180\times 750}\\\\\text{Molality of }C_6H_{12}O_6=0.740m$

Hence, the molality of solution is 0.740 m.

6 0

3 years ago

An atom can be compared to our solar system because: WILL MAKE BRAINLIEST!

Sindrei [870]

Answer:

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Explanation:

sorry if its wrong

5 0

3 years ago

The following reaction has an activation energy of 262 kJ/mol.

Hitman42 [59]

Answer: i really dont know srry

Explanation:

4 0

3 years ago