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Yuki888 [10]
3 years ago
11

How much heat is evolved in converting 1.00 mol of steam at 140.0 ?C to ice at -45.0 ?C? The heat capacity of steam is 2.01 J/(g

??C) and of ice is 2.09 J/(g??C).
Chemistry
1 answer:
Serhud [2]3 years ago
5 0
The chemical formula for steam is H2O(g)

mass of steam = mole of steam * molar mass of H2O
= 1 * (1*2+16) = 18 g

by E = m * c * change in temperature,
From 140C steam to 100C steam
18 * 2.01 * (140-100) = 1447.2J

latent heat of vaporization of water = 2.26x10^6 J/kg* 0.018 = 40680 J

From 100C water to 0C water
18 * 4.2 * (100-0) = 7560 J

latent heat of fusion of ice = 334 J/g * 18 g = 6012 J

From 0C ice to -45C ice
18 * 2.09 * (45-0)
= 1692.9 J

1447.2 + 40680 + 7560 + 6012 + 1692.9 = 57392.1 J
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topjm [15]

Answer:

0.302 moles

Explanation:

Data given

Mass of Pb(NO₃)₂ = 100 g

Moles of Pb(NO₃)₂ = ?

Solution:

To find mole we have to know about molar mass of Pb(NO₃)₂  

So,

Molar mass of Pb(NO₃)₂  = 207 + 2[14 + 3(16)]

                                           = 207 + 2[14 + 48]

                                           = 207 + 124

Molar mass of Pb(NO₃)₂  = 331 g/mol

Formula used :

                no. of moles = mass in grams / molar mass

Put values in above formula

                   no. of moles = 100 g / 331 g/mol

                   no. of moles = 0.302 moles

no. of moles of  Pb(NO₃)₂ = 0.302 moles

7 0
3 years ago
Three parts of an atom
ehidna [41]

Answer:

the atom can be broken down into three constituents parts – protons, neutron, and electrons.

Explanation:

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5 0
3 years ago
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What is the theoretical yield of aluminum oxide if 1.40 mol of aluminum metal is exposed to 1.35 mol of oxygen?
jasenka [17]

Answer:

71.372 g or 0.7 moles

Explanation:

We are given;

  • Moles of Aluminium is 1.40 mol
  • Moles of Oxygen 1.35 mol

We are required to determine the theoretical yield of Aluminium oxide

The equation for the reaction between Aluminium and Oxygen is given by;

4Al(s) + 3O₂(g) → 2Al₂O₃(s)

From the equation 4 moles Al reacts with 3 moles of oxygen to yield 2 moles of Aluminium oxide.

Therefore;

1.4 moles of Al will require 1.05 moles (1.4 × 3/4) of oxygen

1.35 moles of Oxygen will require 1.8 moles (1.35 × 4/3) of Aluminium

Therefore, Aluminium is the rate limiting reagent in the reaction while Oxygen is the excess reactant.

4 moles of aluminium reacts to generate 2 moles aluminium oxide.

Therefore;

Mole ratio Al : Al₂O₃ is 4 : 2

Thus;

Moles of Al₂O₃ = Moles of Al × 0.5

                         = 1.4 moles × 0.5

                         = 0.7 moles

But; 1 mole of Al₂O₃ = 101.96 g/mol

Thus;

Theoretical mass of Al₂O₃ = 0.7 moles × 101.96 g/mol

                                            = 71.372 g

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3 years ago
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A student must make a 3 m acid solution using a 5 m acid solution. which of these is the safest way to make the solution?
weqwewe [10]
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