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3 years ago

Please help me with this. i also need to know what the word heat means.

Chemistry

1 answer:

aliina [53]3 years ago

3 0

Heat is like the fire it’s hot.
I think it’s B
Sorry if I’m wrong

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A manufacturing plan has been found guilty of polluting the nearby river. this is pollution

solniwko [45]

Yes it is polluting the river with everything the manufaturing plant gives off such as the chemicals released in the air

6 0

3 years ago

Phosphorous trichloride and phosphorous pentachloride equilibrate in the presence of molecular chlorine according to the reactio

umka21 [38]

Answer : The value of $K_p$ at this temperature is 66.7

Explanation : Given,

Pressure of $PCl_3$ at equilibrium = 0.348 atm

Pressure of $Cl_2$ at equilibrium = 0.441 atm

Pressure of $PCl_5$ at equilibrium = 10.24 atm

The balanced equilibrium reaction is,

$PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)$

The expression of equilibrium constant $K_p$ for the reaction will be:

$K_p=\frac{(p_{PCl_5})}{(p_{PCl_3})(p_{Cl_2})}$

Now put all the values in this expression, we get :

$K_p=\frac{(10.24)}{(0.348)(0.441)}$

$K_p=66.7$

Therefore, the value of $K_p$ at this temperature is 66.7

4 0

3 years ago

How many atoms are in 1.14 mol of SO2?<br><br>2.05 x 10 ^24

dlinn [17]

8.863x10^23 molecules SO2

7 0

3 years ago

In which situations is work being done?

inysia [295]

Answer:

2 Andy's car rolls down a hill with the engine off

Explanation:

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6 0

3 years ago

When 220 mL of 1.50x10^-4 M hydrochloric acid is added to 135 mL of 1.75x10^-4 M Mg(OH)2, the resulting solution will be________

siniylev [52]

Answer:

Basic

Explanation:

Considering

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

So,

$Moles =Molarity \times {Volume\ of\ the\ solution}$

For hydrochloric acid :

Molarity = $1.50\times 10^{-4}$ M

Volume = 220 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 220×10⁻³ L

$Moles =1.50\times 10^{-4} \times {220\times 10^{-3}}\ moles$

Moles of hydrochloric acid = 0.000033 moles

For $Mg(OH)_2$ :

Molarity = $1.75\times 10^{-4}$ M

Volume = 135 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 135×10⁻³ L

$Moles =1.75\times 10^{-4} \times {135\times 10^{-3}}\ moles$

Moles of $Mg(OH)_2$ = 0.000024 moles

According to the given reaction:

$Mg(OH)_2_{(aq)}+2HCl_{(aq)}\rightarrow MgCl_2_{(s)}+2H_2O_{(aq)}$

1 mole of $Mg(OH)_2$ reacts with 2 moles of HCl

Also,

0.000024 mole of $Mg(OH)_2$ reacts with 2*0.000024 moles of HCl

Moles of HCl = 0.000048 moles

Available moles of HCl = 0.000033 moles

Limiting reagent is the one which is present in small amount. Thus, HCl is limiting reagent.

Thus, HCL will be consumed completely and $Mg(OH)_2$ will be left over. Thus, the resulting solution will be basic.

4 0

4 years ago