Answer:
2 AgNO₃(aq) + Ca(BrO₃)₂(aq) ⇒ Ca(NO₃)₂(aq) + 2 AgBrO₃(s)
2 Ag⁺(aq) + 2 NO₃⁻(aq) + Ca²⁺(aq) + 2 BrO₃⁻(aq) ⇒ Ca²⁺(aq) + 2 NO₃⁻(aq) + 2 AgBrO₃(s)
2 Ag⁺(aq) + 2 BrO₃⁻(aq) ⇒ 2 AgBrO₃(s)
Explanation:
The question is missing but I think it must be about the chemical equations.
Let's consider the molecular equation that occurs when a solution of silver nitrate and a solution of calcium bromate react.
2 AgNO₃(aq) + Ca(BrO₃)₂(aq) ⇒ Ca(NO₃)₂(aq) + 2 AgBrO₃(s)
The complete ionic equation includes all the ions and the insoluble species.
2 Ag⁺(aq) + 2 NO₃⁻(aq) + Ca²⁺(aq) + 2 BrO₃⁻(aq) ⇒ Ca²⁺(aq) + 2 NO₃⁻(aq) + 2 AgBrO₃(s)
The net ionic equation includes only the ions that participate in the reaction and the insoluble species.
2 Ag⁺(aq) + 2 BrO₃⁻(aq) ⇒ 2 AgBrO₃(s)
Answer: Heat associated with the formation of 100.0 g of carbon dioxide is 1563.2 kJ.
Explanation:
Reaction equation will be as follows.
; 
= -11018 kJ
Mass of 
= 100 g
Hence, moles of present will be calculated as follows.
No. of moles = 
= 
= 2.27 mol
Therefore, heat produced by 2.27 mol for the given reaction will be calculated as follows.
= 1563.2 kJ
Thus, we can conclude that heat associated with the formation of 100.0 g of carbon dioxide is 1563.2 kJ.
<span>In 5.70 mol of Hafnium there are 34,326 208 203*10^23 atoms.</span>
Bond Order = [Σ (bonding e-) - Σ (antibonding e-)]/2
<span>Be2 = 4e = σ1(2e) σ2*(2e) σ3(0) π1(0) π2*(0) σ4*(0) bo = 0 </span>
<span>[Be2]+ = 3e = σ1(2e) σ2*(1e) σ3(0) π1(0) π2*(0) σ4*(0) bo = 0.5 </span>
<span>[Be2]+ would be more likely to exist since it has a bond order of 0.5 whereas Be2 has zero bond order</span>
