Molar mass of copper chloride is 134.45 g/mole, so the mole of 10.5 g copper chloride is 10.5/134.45 = 0.078 mole. Molar mass of aluminum is 27 g/mole, so the mole of 12.4 g aluminium is 12.4/27 = 0.46 mole. The formula of this reaction is as follows, 2Al + 3CuCl2 ⇒ 2AlCl3 + 3Cu. Thus the molar ratio of the reactants is Al:CuCl2 = 2:3. So to react with 0.078 mole of copper chloride, will need 0.078 x 2/3 = 0.052 moles of aluminum which is less than the given amount (0.46mole). Therefore, copper chloride is the limiting reactant.
Answer:
The right statement is " the Pathway A-C-D involves a catalyst and is faster than A-B-D"
Explanation:
Catalyst is a substance that increases the rate of a chemical reaction by lowering the activation energy Eₐ (i.e. by changing the reaction pathway), which Catalyst is not consumed in the catalyzed reaction and can continue to act repeatedly.
From the attached figure one can see that the path way A-C-D has different pathway and lower activation energy (Eₐ) than the pathway A-B-D, this means that the pathway A-C-D is a catalyzed pathway and it is faster than A-B-D.
So, the right statement is " the Pathway A-C-D involves a catalyst and is faster than A-B-D"
