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Gnom [1K]
3 years ago
6

Two boats start together and race across a 68-km-wide lake and back. boat a goes across at 68 km/h and returns at 68 km/h. boat

b goes across at 34 km/h, and its crew, realizing how far behind it is getting, returns at 102 km/h. turnaround times are negligible, and the boat that completes the round trip first wins.
Physics
1 answer:
e-lub [12.9K]3 years ago
4 0
Boat speed is 68km/h both to and fro.
boat b speed to is 34km/h and back is 102km/h
time taken by boat to is distance/speed= 68 km/68km/h=1 hour
and fro is 68km/68km/h=1 hour
for the whole trip boat a took 2 hours
boat b speed to is 34km/h and distance is 68km, so it took 68km/34km/h = 2 hours to and fro it took 68km/102km/h=0.67 hours
for the whole trip boat b took 2.67 hours
so boat a is the winner as it took 2 hours to complete the challenge.
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3 years ago
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Answer:

Depending on the relative position of the Earth the Sun and Neptune in the Earths orbit the distances are;

The closest (minimum) distance of Neptune from the Earth is 29 AU

The farthest (maximum) distance of Neptune fro the Earth is 31 AU

Explanation:

The following parameters are given;

The distance from the Earth to the Sun = 1 AU

The distance of Neptune from the Earth = 30 AU

We have;

When the Sun is between the Earth and Neptune, the distance is found by the relation;

Distance from the Earth to Neptune = 30 + 1 = 31 AU

When the Earth is between the Sun  and Neptune, the distance is found by the relation;

Distance from the Earth to Neptune = 30 - 1 = 29 AU

Therefore, the closest distance from Neptune to the Earth in the Earth's Orbit is 29 AU

The farthest distance from Neptune to the Earth in the Earth's orbit is 31 AU.

8 0
3 years ago
Which describes an interaction within the musculoskeletal system?
rosijanka [135]

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7 0
3 years ago
Read 2 more answers
A hammer slides down a roof that makes a 30.0°angle with the horizontal. What are the magnitudes of the components of the hammer
dlinn [17]
<h2>Answer:7.14ms^{-1},4.125ms^{-1}</h2>

Explanation:

Whenever an object is moving in a 2D frame,its motion can be analysed as if it is travelling in two independent 1D frames.

One of such independent 1D frames are along horizontal and another along vertical.

Let v be the total velocity.

Given that,v=8.25ms^{-1}

We call the horizontal velocity as v_{h} and the vertical velocity as v_{v}.

v_{h}=vCos\alpha

v_{v}=vSin\alpha

where \alpha is the angle between the object and horizontal.

It is given that \alpha =30^{0}

v_{h}=8.25\times Cos(30^{0})=7.14ms^{-1}

v_{v}=8.25\times Sin(30^{0})=4.125ms^{-1}

7 0
3 years ago
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Schach [20]

Answer:

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Explanation:

Given data:

R1=3 Ω

R2=8 Ω

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Now,

To Find,

R=?

Formula

R=R1+R2+R3

put the values,

R=3+8+14

R=25Ω

6 0
3 years ago
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