Consider the length of diagonal is 8.5 cm instead of 8.5 m because length of perpendiculars are in cm.
Given:
Length of the diagonal of a quadrilateral = 8.5 cm
Lengths of the perpendiculars dropped on it from the remaining opposite vertices are 3.5 cm and 4.5 cm.
To find:
The area of the quadrilateral.
Solution:
Diagonal divides the quadrilateral in 2 triangles. If diagonal is the base of both triangles then the lengths of the perpendiculars dropped on it from the remaining opposite vertices are heights of those triangles.
According to the question,
Triangle 1 : Base = 8.5 cm and Height = 3.5 cm
Triangle 2 : Base = 8.5 cm and Height = 4.5 cm
Area of a triangle is

Using this formula, we get


and


Now, area of the quadrilateral is



Therefore, the area of the quadrilateral is 34 cm².
Okie. i get it. you guys must like sports a lot
The base's length is 8 and it's width is 7, so it's perimeter will be

. To find the lateral area you shoul multiply this with it's height. So,

(h is height).