Answer:
1. Measure the temperature of the boxes and leave them unconnected.
2. Norton reduces his circuit down to a single resistance in parallel with a constant current source. A real-life Norton equivalent circuit would be continuously wasting power (as heat) as the current source dumps energy into the resistor, even when externally unconnected, while a Thevenin equivalent circuit would sit there doing nothing.
3. The Norton equivalent box would get warm and eventually run out of power. The Thevenin equivalent box would stay at ambient temperature.
Answer:
The note in this question is not an instrument that is negotiable under Article 3 of the U.C.C. Furthermore, it is not payable at any given time on demand due to the fact that principal repayment is not covered at a specified period of time. It shows that the acceleration clause is viable for the payment of the amount upon the default of the maker. This is also for an indefinite period of time.
Explanation:
The note in this question is not an instrument that is negotiable under Article 3 of the U.C.C. Furthermore, it is not payable at any given time on demand due to the fact that principal repayment is not covered at a specified period of time. It shows that the acceleration clause is viable for the payment of the amount upon the default of the maker. This is also for an indefinite period of time.
Answer:
ssssssssssssssssssssssssssssssss
Answer: 1.98 × 10^4 N
Explanation:
Form similar triangle ADE and ABC
a/x= 2/3, a=2/3x
Width of the strip w= 2(4+a) = 8+2a
W= 8 +2 (2/3x)= 8+4/3x
Area of the strip = w Δx
(8 +4/3x) Δx
Pressure on the strip p= pgx= 10^3 ×9.81x= 9810x
But,
Force= Pressure × area= 9810x × (8+4/3x)Δx
Adding the forces and taking lim n to infinity
F total= lim n--> infinity E 9810x × (8+4/3x)Δx
Ftotal= Integral 2,0 9810x × (8+4/3x)Δx
F total= 9810 integral 2, 0 (8+4/3x)dx
= 9810(8+x^2/2 + 4/3x^3/3)2,0
=9810(4x^2 + 4/9x^3)
=9810(4x2^2 + 4/9×2^3-0)
=9810(16 + 32/9)
Hydrostatic force as an integral
Ft= 19.18 ×10^4N
