Answer:
Available energy = 35 x 10⁶ J
Explanation:
Given:
Amount of energy (Q) = 21 gj = 21 x 10⁹ J
Temperature T1 = 600 k
Temperature T0 = 27 + 273 = 300k
Find:
Available energy
Computation:
Available energy = Q[1/T0 - 1/T1]
Available energy = 21 x 10⁹ J[1/300 - 1/600]
Available energy = 35 x 10⁶ J
Answer:
Explanation:
Can you please place the square roots in a proper manner so I may assist you?
Briefly outline the caloric theory about the nature of heat
Answer:800N
Explanation:
Force of repulsion = kq1q2/r^2
Q1= 20*10^-6
Q2=100*10^-6
R=150cm=0.15m
K= 9*10^9
F= 2*10^-5*1*10^-4*9*10^9/(0.15)^2
F= 2*1*9*10^-5-4+9/(0.15)^2
F= 18*10^0/(0.15)^2
F=18/0.0225
F=800N