Question

What is the equation of the line that passes through the point (-5,2) and has a slope of 4/5

Answer 1

Answer:

y = $\frac{4}{5}$ x + 6

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = $\frac{4}{5}$ , then

y = $\frac{4}{5}$ x + c ← is the partial equation

To find c substitute (- 5, 2 ) into the partial equation

2 = - 4 + c ⇒ c = 2 + 4 = 6

y = $\frac{4}{5}$ x + 6 ← equation of line

Answer 2

Answer:

Below.

Step-by-step explanation:

Use the point-slope form of a straight line.

y - y1 = m(x - x1)

Here m = 4/5, x1 = -5 and y1 = 2, so

y - 2 = 4/5(x - -5))

y - 2 = 4/5 x  + 4

y = 4/5x + 6 is the answer in slope-intercept form.

Standard form:

Multiply through by 5:

5y = 4x + 30

4x - 5y = -30 is the answer in standard form.