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vovangra [49]
3 years ago
6

What is the equation of the line that passes through the point (-5,2) and has a slope of 4/5

Mathematics
2 answers:
Lady bird [3.3K]3 years ago
7 0

Answer:

y = \frac{4}{5} x + 6

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = \frac{4}{5} , then

y = \frac{4}{5} x + c ← is the partial equation

To find c substitute (- 5, 2 ) into the partial equation

2 = - 4 + c ⇒ c = 2 + 4 = 6

y = \frac{4}{5} x + 6 ← equation of line

Ainat [17]3 years ago
4 0

Answer:

Below.

Step-by-step explanation:

Use the point-slope form of a straight line.

y - y1 = m(x - x1)

Here m = 4/5, x1 = -5 and y1 = 2, so

y - 2 = 4/5(x - -5))

y - 2 = 4/5 x  + 4

y = 4/5x + 6 is the answer in slope-intercept form.

Standard form:

Multiply through by 5:

5y = 4x + 30

4x - 5y = -30 is the answer in standard form.

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The perpendicular bisector of the line joining G(9, 8) and H(3, 2) is perpendicular to the line joining G(9, 8) and H(3, 2) and passes through the midpoint of line joining G(9, 8) and H(3, 2).

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