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d1i1m1o1n [39]
2 years ago
12

I need help with this question

Engineering
1 answer:
Roman55 [17]2 years ago
6 0

Answer:

last one 8;2per leg

Explanation:

sorry if I got it wrong

You might be interested in
What are the steps to execute an instruction by cpu?What is the function of DMA controller.
JulijaS [17]

Explanation:

1. A sequence of instructions is stored in memory.

2. The memory address wherever the first instruction is found is copied to the instruction pointer.

3. The CPU sends the address within the instruction pointer to memory on the address bus.

4. The CPU sends a “read” signal to the control bus.

5. Memory responds by sending a copy of the state of the bits at that memory location on the

data bus, that the CPU then copies into its instruction register.

6. The instruction pointer is automatically incremented to contain the address of the next

instruction in memory.

7. The CPU executes the instruction within the instruction register.

8. Go to step 3

Steps 3, 4, and 5 are called an instruction fetch. Notice that steps 3 – 8 constitute a cycle, the instruction execution cycle. It is shown graphically below.

A DMA controller can generate memory addresses and initiate memory read or write cycles. It contains several hardware registers that can be written and read by the CPU. These include a memory address register, a byte count register, and one or more control registers.

4 0
3 years ago
A pin must be inserted into a collar of the same steel using an expansion fit. The coefficient of thermal expansion of the metal
nirvana33 [79]

Answer:

a)  the temperature to which the pin must be cooled for assembly is T_2 = -101.89^ \ ^0}C

b) the radial pressure at room temperature after assembly is P_f = 62.8 \ MPa

c) the  safety factor in the resulting assembly = 6.4

Explanation:

Coefficient of thermal expansion \alpha = 12.3*10^{-6} \  ^0 C

Yield strength \sigma_y = 400 MPa

Modulus of elasticity (E) = 209 GPa

Room Temperature T_1 = 20°C

outer diameter of the collar D_o = 95 \ mm

inner diameter of the collarD_i = 60 \ mm

pin diameter D_p = 60.03 \ mm

Clearance c = 0.06 mm

a)

The temperature to which the pin must be cooled for assembly can be calculated by using the formula:

(D_i - c )-D_p = \alpha * D_p(T_2-T_1)

(60-0.06)-60.03=12.3*10^{-6}*60.03(T_{2}-20^{0}C)

-0.09 = 7.38369*10^{-4}(T_{2}-20^{0}C)

-0.09 = 7.38369*10^{-4}T_2  \ \ - \ \ 0.01476738

-0.09 +  0.01476738 = 7.38369*10^{-4}T_2

−0.07523262 =7.38369*10^{-4}T_2

T_2 = \frac{-0.07523262}{7.38369*10^{-4}}

T_2 = -101.89^ \ ^0}C

b)

To determine the radial pressure at room temperature after assembly ;we have:

P_f = \frac{E * (D_p-D_i)(D_o^2-D_1^2)}{D_i*D_o} \\ \\ \\  P_f = \frac{209*10^9* 0.03(95^2-60^2)}{60*95^2}  \\ \\ P_f = 62815789.47 \ Pa \\ \\ P_f = 62.8 \ MPa

c)  the safety factor of the resulting assembly is calculated as:

safety factor =  \frac{Yield \ strength }{walking \ stress}

safety factor =  \frac{400}{62.8}

safety factor = 6.4

Thus, the  safety factor in the resulting assembly = 6.4

4 0
3 years ago
The phasor technique makes it pretty easy to combine several sinusoidal functions into a single sinusoidal expression without us
devlian [24]

Answer:

The phasor technique can't be applied directly in the following cases:

a) 45 sin(2500t – 50°) + 20 cos(1500t +20°)

b) 100 cos(500t +40°) + 50 sin(500t – 120°) – 120 cos(500t + 60°)

c)  -100 sin(10,000t +90°) + 40 sin(10, 100t – 80°) + 80 cos(10,000t)

d)  75 cos(8t+40°) + 75 sin(8t+10°) – 75 cos(8t + 160°)

Explanation:

For a) and c), it is not possible to use the phasor technique, due this technique is only possible when the sinusoidal signals to be combined are all of the same frequency.

This is due to the vector representing a signal is showed as a fixed vector in the graph( which magnitude is equal to the amplitude of the sinusoid and his angle is the phase angle with respect to cos (ωt)), which is rotating at an angular speed equal to the angular frequency of the sinusoidal signal that represents, like a radius that shows a point rotating in a circular uniform movement.

This rotating vector represents a sinusoidal signal, in the form of a cosine (as the real part of the complex function e^{j(wt+\alpha)}), so it is not possible to combine with functions expressed as a sine, even though both  have  the same frequency.

If we look at the graphs of cos (ωt) and sin (ωt) we can say that the sin lags the cos in 90º, so we can say the following:

sin (ωt) = cos (ωt-90º)

This means that in order to be able to represent a sine function  as a cosine, we need to rotate it 90º in the plane clockwise.

This is the reason why before doing this transformation, it is not possible to use the phasor technique for b) and d).

8 0
3 years ago
Production of pressure vessels is fastening an open-ended cylinder and two rigid plates with bolts. The cylinder made of brass.
marysya [2.9K]

Answer:

The pressure that the container will start to leak is 154.87 psi

Explanation:

Force on end plates F = p(πR²) ⇒ pπR²

There is an equal reaction from four bolts ∴ F = pπR² / 4 .............. (1)

due to force on bolt, each bolt stretch by \sigma_b

Therefore; \sigma_b = \frac{F_bL}{A_bE_b} .........................(2)

Leaking will start when tightening is outstretched by half turn per 16 turns per inch.

Cylinder experience a radial expansion as p increases. it is accompanied by poisson contraction \sigma_c in axial direction. That is, the bolt do not have to experience a long stretch before the pressure breaks off the plate.

\sigma_b + \sigma_c = \frac{1}{2} *\frac{1}{16} = \frac{1}{32} ...................... (3)

Axial deformation \sigma_c of cylinder = L times axial ∈₀

<em>see continuation in attached picture in writing to get the value of Pressure: since we have the value of P</em>

R=8", L=16", t=0.125"

Area of bolts A_b = \frac{\pi}{4}(\frac{7}{16})^2 = 0.150 inch^2

E_c = E_{cylinder} = 125

E_b = E_{bolt} = 200

V for brass = 0.3

P = \frac{1}{8*8*16} [\frac{0.150*12.5*200*0.125*10^9}{\pi*8*125*0.125+4*0.3*0.150*200}]

p = 1.67797.183 P ⇒ 154.87 psi

7 0
4 years ago
The wires each have a diameter of 12 mm, length of 0.6 m, and are made from 304 stainless steel. Determine the magnitude of forc
Sonbull [250]

Answer:

Magnitude of force P = 25715.1517 N

Explanation:

Given - The wires each have a diameter of 12 mm, length of 0.6 m, and are made from 304 stainless steel.

To find - Determine the magnitude of force P so that the rigid beam tilts 0.015∘.

Proof -

Given that,

Diameter = 12 mm = 0.012 m

Length = 0.6 m

\theta = 0.015°

Youngs modulus of elasticity of 34 stainless steel is 193 GPa

Now,

By applying the conditions of equilibrium, we have

∑fₓ = 0, ∑f_{y} = 0, ∑M = 0

If ∑M_{A} = 0

⇒F_{BC}×0.9 - P × 0.6 = 0

⇒F_{BC}×3 - P × 2 = 0

⇒F_{BC} = \frac{2P}{3}

If ∑M_{B} = 0

⇒F_{AD}×0.9 = P × 0.3

⇒F_{AD} ×3 = P

⇒F_{AD} = \frac{P}{3}

Now,

Area, A = \frac{\pi }{4} X (0.012)^{2} = 1.3097 × 10⁻⁴ m²

We know that,

Change in Length , \delta = \frac{P l}{A E}

Now,

\delta_{AD} = \frac{P(0.6)}{3(1.3097)(10^{-4}) (193)(10^{9}  } = 9.1626 × 10⁻⁹ P

\delta_{BC} = \frac{2P(0.6)}{3(1.3097)(10^{-4}) (193)(10^{9}  } = 1.83253 × 10⁻⁸ P

Given that,

\theta = 0.015°

⇒\theta = 2.618 × 10⁻⁴ rad

So,

\theta =  \frac{\delta_{BC} - \delta_{AD}}{0.9}

⇒2.618 × 10⁻⁴ = (  1.83253 × 10⁻⁸ P - 9.1626 × 10⁻⁹ P) / 0.9

⇒P = 25715.1517 N

∴ we get

Magnitude of force P = 25715.1517 N

6 0
3 years ago
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