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Vadim26 [7]
3 years ago
15

La iluminación de la superficie de un patio amplio es 1600 lx cuando el ángulo de elevación del sol 53°. Calcular la iluminación

cuando el ángulo de elevación del Sol sea 37°
Engineering
1 answer:
gregori [183]3 years ago
6 0

Answer:

 I = 1205.69 Lx

Explanation:

The irradiation or intensity of the solar radiation on the earth is maximum for the vertical fire, with a value I₀

          I = I₀ sin θ

in this case with the initial data we can calculate the initial irradiance

         I₀ = \frac{I}{sin  \ \theta }

         I₀ = 1600 /sin 53

         I₀ = 2003.42 lx

for when the angle is θ = 37º

         I = 2003.42 sin 37

         I = 1205.69 Lx

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Air flows through a device such that the stagnation pressure is 0.4 MPa, the stagnation temperature is 400°C, and the velocity i
RoseWind [281]

To solve this problem it is necessary to apply the concepts related to temperature stagnation and adiabatic pressure in a system.

The stagnation temperature can be defined as

T_0 = T+\frac{V^2}{2c_p}

Where

T = Static temperature

V = Velocity of Fluid

c_p = Specific Heat

Re-arrange to find the static temperature we have that

T = T_0 - \frac{V^2}{2c_p}

T = 673.15-(\frac{528}{2*1.005})(\frac{1}{1000})

T = 672.88K

Now the pressure of helium by using the Adiabatic pressure temperature is

P = P_0 (\frac{T}{T_0})^{k/(k-1)}

Where,

P_0= Stagnation pressure of the fluid

k = Specific heat ratio

Replacing we have that

P = 0.4 (\frac{672.88}{673.15})^{1.4/(1.4-1)}

P = 0.399Mpa

Therefore the static temperature of air at given conditions is 72.88K and the static pressure is 0.399Mpa

<em>Note: I took the exactly temperature of 400 ° C the equivalent of 673.15K. The approach given in the 600K statement could be inaccurate.</em>

3 0
3 years ago
What gives thrill in a roller coaster? High speed or Changing acceleration? Explain your answer.
iris [78.8K]

Answer:

They both work together in order to create a good experience for the passenger, but I think that the answer is changing acceleration because when  the rollercoaster changes acceleration it gives it speed.

Explanation:

I really hope this helps.

8 0
3 years ago
Read Shakespeare's "Sonnet 100.”
liraira [26]

Answer: quatrain

Explanation:

Reading the Shakespeare's "Sonnet 100", we can infer that the underlined section is referred to as a quatrain.

The quatrain simply refers to a type of stanza that is made up of four lines. For example, based on the information given, we can deduce that the rhyme scheme for the second quatrain is given as cdcd.

7 0
3 years ago
A very large plate is placed equidistant between two vertical walls. The 10-mm spacing between the plate and each wall is filled
Vikentia [17]

Answer:

Force per unit plate area is 0.1344 N/m^{2}

Solution:

As per the question:

The spacing between each wall and the plate, d = 10 mm = 0.01 m

Absolute viscosity of the liquid, \mu =1.92\times 10^{- 3} Pa-s

Speed, v = 35 mm/s = 0.035 m/s

Now,

Suppose the drag force that exist between each wall and plate is F and F' respectively:

Net Drag Force = F' + F''

F = \tau A

where

\tau = shear stress

A = Cross - sectional Area

Therefore,

Net Drag Force, F = (\tau ' +\tau '')A

\frac{F}{A} = \tau ' +\tau ''

Also

F = \frac{\mu v}{d}

where

\mu = dynamic coefficient of viscosity

Pressure, P = \frac{F}{A}

Therefore,

\frac{F}{A} = \frac{\mu v}{d} + \frac{\mu v}{d} = 2\frac{\mu v}{d}

\frac{F}{A} = 2\frac{1.92\times 10^{- 3}\times 0.035}{0.010} = 0.01344 N/m^{2}

8 0
3 years ago
2. Using an RLC circuit to design a band-reject filter, with the two cut off frequencies 40k and 90k Hz. Design the values of R,
nadya68 [22]

Answer:

C = 59.17 nF

Q = 2.6

Explanation:

given data

frequencies = 40k Hz

frequencies  = 90k Hz

solution

we take here R, L C take in series

so cut off frequency is express as

Wc1 = -\frac{R}{2L}+ \sqrt{(\frac{R}{2L})^2+\frac{1}{LC}}   =  40000

wc2 = \frac{R}{2L}+ \sqrt{(\frac{R}{2L})^2+\frac{1}{LC}}    =  90000

so here

wc2 - wc1 will be

wc2 - wc1 = 90000 - 40000 = 50000

so

\frac{R}{L} =  50000

we consider here R is 500

so  L = \frac{500}{50000}  

L = 10 m H

and here total cut off frequency is

total cut off frequency = 40000 + 90000 = 130000

so capacitance will be

capacitance  C is =  \frac{1}{10\times 10^{-3}\times 130000^2}  

so C = 59.17 nF

quality factor Q will be

Q = \frac{130000}{50000}  

Q = 2.6

4 0
3 years ago
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