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3 years ago

What happens to the gravitational force between two objects if:

Physics

1 answer:

rewona [7]3 years ago

6 0

Answer:

A. The force of attraction will also increase i.e double.

B. The force of attraction will increase by a multiple of 4.

C. The force of attraction will decrease by a factor of 4

Explanation:

We'll begin by writing the formula for calculating the gravitational force between two objects. This is given below:

F = GM₁M₂/r²

Where:

F: is the force of attraction between the two objects.

G: is the gravitational constant.

M₁ and M₂: are the masses of the two objects.

r: is the distance between two objects.

F = GM₁M₂/r²

From the formula, we can say that:

The force (F) of the attraction between the two objects is directly proportional to the masses (M₁ and M₂) of the objects and inversely proportional to the square of the distance between (r) the two objects.

A. Determination of the force of attraction when the mass of one is doubled.

Since the force (F) is directly proportional to the the masses (M₁ and M₂) of the objects, if the mass of one is double, the force of attraction will also increase i.e double.

B. Determination of the force of attraction when the masses of both is doubled.

Since the force (F) is directly proportional to the the masses (M₁ and M₂) of the objects, if the masses of both is double, the force of attraction will also increase by a multiple of 4.

C. Determination of the force of attraction between the distance between them is doubled.

Since the force (F) of the attraction between the two objects is inversely proportional to the square of the distance between (r) the two objects. If the distance between them is doubled, the force of attraction will decrease by a factor of 4

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Spitting cobras can defend themselves by squeezing muscles around their venom glands to squirt venom at an attacker. Suppose a s

Alenkasestr [34]

Answer: 1.289 m

Explanation:

The path the cobra's venom follows since it is spitted until it hits the ground, is described by a parabola. Hence, the equations for parabolic motion (which has two components) can be applied to solve this problem:

<u>x-component: </u>

$x=V_{o}cos\theta t$ (1)

Where:

$x$ is the horizontal distance traveled by the venom

$V_{o}=3.10 m/s$ is the venom's initial speed

$\theta=47\°$ is the angle

$t$ is the time since the venom is spitted until it hits the ground

<u>y-component: </u>

$y=y_{o}+V_{o}sin\theta t+\frac{gt^{2}}{2}$ (2)

Where:

$y_{o}=0.44 m$ is the initial height of the venom

$y=0$ is the final height of the venom (when it finally hits the ground)

$g=-9.8m/s^{2}$ is the acceleration due gravity

Let's begin with (2) to find the time it takes the complete path:

$0=0.44 m+3.10 m/s sin\theta(47\°)+\frac{-9.8m/s^{2} t^{2}}{2}$ (3)

Rewritting (3):

$-4.9 m/s^{2} t^{2} + 2.267 m/s t + 0.44 m=0$ (4)

This is a quadratic equation (also called equation of the second degree) of the form $at^{2}+bt+c=0$ , which can be solved with the following formula:

$t=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$ (5)

Where:

$a=-4.9 m/s^{2$

$b=2.267 m/s$

$c=0.44 m$

Substituting the known values:

$t=\frac{-2.267 \pm \sqrt{2.267^{2}-4(-4.9)(0.44)}}{2(-4.9)}$ (6)

Solving (6) we find the positive result is:

$t=0.609 s$ (7)

Substituting (7) in (1):

$x=(3.10 m/s)cos(47\°)(0.609 s)$ (8)

We finally find the horizontal distance traveled by the venom:

$x=1.289 m$

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3 years ago

Which of the following has the most potential energy?

Alex

A Car at the top of a hill.

It is because in that case, produce of mass and height is highest which is directly proportional to potential energy

In short, Your Answer would be Option A

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2 years ago

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devlian [24]

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2 years ago

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suter [353]

Do u know Chinese ?if yes I can explain to u easily

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