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Liono4ka [1.6K]
3 years ago
12

I. What is the initial velocity of the car?

Physics
1 answer:
qaws [65]3 years ago
6 0

Answer:

I. 0 m/s

II. 20 m/s

III. Part BC

Explanation:

I. Determination of the initial velocity.

From the diagram given above,

The motion of the car starts from the origin. This implies that the car start from rest and as such, the initial velocity of the car is 0 m/s

II. Determination of the maximum velocity attained.

From the diagram given above, we can see clearly that the maximum velocity is 20 m/s.

III. Determination of the part of the graph that represents zero acceleration.

It important that we know the meaning of zero acceleration.

Zero acceleration simply means the car is not accelerating. This can only be true when the car is moving with a constant velocity.

From the graph given above, the car has a constant velocity between B and C.

Therefore, part BC illustrates zero acceleration.

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Answer:

An object has the MOST kinetic energy when it's movement is the GREATEST.

Explanation:

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A parallel-plate capacitor is connected to a battery until it is fully charged. Then, the capacitor is disconnected from the bat
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Answer:

The potential between the plates will decrease.

Explanation:

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Furthermore, the dielectric effect will make the electric field of the charged capacitor which is not connected to a source of supply to decrease.

Now, when the battery is removed, the charge Q remains constant and Capacity C will increase.

Formula for the potential difference is here;

V = Q/C

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A rifle fires a 2.01 10-2-kg pellet straight upward, because the pellet rests on a compressed spring that is released when the t
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Answer:

The value of spring constant is 266.01 \frac{N}{m}

Explanation:

Given:

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Height difference of pellet rise h_{f} - h_{o} = 6.03 m

Spring compression x = 9.45 \times 10^{-2} m

From energy conservation law,

Spring potential energy is stored into potential energy,

  mg(h_{f} -h_{o})  = \frac{1}{2} kx^{2}

Where k = spring constant, g = 9.8 \frac{m}{s^{2} }

  k = \frac{2mg(h_{f} -h_{o} )}{x^{2} }

  k = \frac{2 \times 9.8 \times 6.03\times 2.01 \times 10^{-2} }{(9.45\times 10^{-2} )^{2} }

  k = 266.01 \frac{N}{m}

Therefore, the value of spring constant is 266.01 \frac{N}{m}

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Light is incident on an air-water interface at an angle of 30 degree to the normal. What angle does the refracted ray make with
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Answer:

22 degree

Explanation:

Angle of incidence, i = 30 degree

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As the ray of light travels from rarer medium to denser medium, that mean air to water, the refraction takes place.

According to Snell's law,

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Where, r be the angle of refraction

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Sin r = 0.375

r = 22 degree

Thus, the angle of refraction is 22 degree.

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