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3 years ago

I. What is the initial velocity of the car?

Physics

1 answer:

qaws [65]3 years ago

6 0

Answer:

I. 0 m/s

II. 20 m/s

III. Part BC

Explanation:

I. Determination of the initial velocity.

From the diagram given above,

The motion of the car starts from the origin. This implies that the car start from rest and as such, the initial velocity of the car is 0 m/s

II. Determination of the maximum velocity attained.

From the diagram given above, we can see clearly that the maximum velocity is 20 m/s.

III. Determination of the part of the graph that represents zero acceleration.

It important that we know the meaning of zero acceleration.

Zero acceleration simply means the car is not accelerating. This can only be true when the car is moving with a constant velocity.

From the graph given above, the car has a constant velocity between B and C.

Therefore, part BC illustrates zero acceleration.

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Jane works at a grocery store. She has a large crate of Bananas with a mass of 13 kg to move to the produce aisle.

sdas [7]

PART a)

As we know that weight is product of mass and gravity

so here we have

$W = mg$

$W = 13(9.8) = 127.4 N$

Part B)

Normal force is counter balanced by weight of the crate

so here we have

N = W = 127.4 N

PART C)

As we know that

F = ma

now we have

m = 13 kg

F = 40 N

now we have

$40 = 13(a)$

$a = 3.08 m/s^2$

Part D)

Maximum static friction force is given as

$F_s = \mu_s N$

here we know that

$\mu_s = 0.2$

now we have

$F_s = 0.2(127.4) = 25.48 N$

PART E)

Since applied force on the block is

F = 12 N

Now since applied force is less than maximum static friction force

So it will not slide

So here friction force will be same as applied force

Static friction = 12 N

PART f)

Kinetic friction force is given as

$F_k = \mu_k N$

here we know that

$\mu_k = 0.15$

now friction force is

$F_k = 0.15(127.4) = 19.11 N$

now we have

$F_{net} = F - F_k$

$F_{net} = 40 - 19.11$

$F_{net} = 20.89 N$

Part g)

as we know that

F = ma

$20.89 = 13a$

$a = 1.61 m/s^2$

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3 years ago

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Yuri [45]

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How can resonance overcome damping of an oscillating system?

Aneli [31]

Answer:

When one system vibrating at its natural frequency is put closer to a stationary system, the stationary system receives impulses.

At resonant frequency, the system vibrating at its own natural frequency suddenly goes on decreasing in order to cope with neighboring system.

These decrease in frequency is known as damping.

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3 years ago

What is the density of a substance that has a mass of 453g and a volume of 224mL?

Mrrafil [7]

Density is mass per unit volume. In this case, the unit is g/ml
Mass=453g ρ=453g/224ml
Volume=224ml ρ=2.022g/ml(rounded to nearest hundredth)
Density=?
ρ=mass/volume
Therefore the density of the substance is 2.022g/ml

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3 years ago

A copper rod of length 27.5 m has its temperature increases by 35.9 degrees celsius. how much does its length increase?(unit=m)

gavmur [86]

<h2>The increase in length = 1.87 x 10⁻²</h2>

Explanation:

When copper rod is heated , its length increases

The increase in length can be found by the relation

L = L₀ ( 1 + α ΔT )

here L is the increased length and L₀ is the original length

α is the coefficient of linear expansion and ΔT is the increase in temperature .

The increase in length = L - L₀ = L₀ x α ΔT

Substituting all these value

Increase in length = 27.5 x 1.7 x 10⁻⁵ x 35.9

= 1.87 x 10⁻² m

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