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Genrish500 [490]
2 years ago
9

The relationship between distance from the sun and orbital period is that as the distance from the sun increases, the orbital pe

riod increases.
We can see this because as we go through the planets in our solar system, the farther away they are from the Sun, the longer their orbital period becomes. For example, Mercury is about 67 million km away from the Sun and has an orbital period of 88 days, where as Neptune is about 4.5 billion km away from the Sun and has an orbital period of 165 years.

This tells us that as the distance from the sun increases, gravity _________________. Because gravity _______________, the orbital period is __________________.
Physics
1 answer:
iren [92.7K]2 years ago
4 0
Second law is it:))))))))
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A rectangular loop of area A is placed in a region where the magnetic field is perpendicular to the plane of the loop. The magni
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Answer:

Induced emf, \epsilon=-A\dfrac{B_{max}e^{-t/\tau}}{\tau}

Explanation:

The varying magnetic field with time t is given by according to equation as :

B=B_{max}e^{-t/\tau}

Where

B_{max}\ and\ t are constant

Let \epsilon is the emf induced in the loop as a function of time. We know that the rate of change of magnetic flux is equal to the induced emf as:

\epsilon=-\dfrac{d\phi}{dt}

\epsilon=-\dfrac{d(BA)}{dt}

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\epsilon=-A\dfrac{d(B_{max}e^{-t/\tau})}{dt}

\epsilon=A\dfrac{B_{max}e^{-t/\tau}}{\tau}

So, the induced emf in the loop as a function of time is A\dfrac{B_{max}e^{-t/\tau}}{\tau}. Hence, this is the required solution.

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