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Genrish500 [490]
2 years ago
9

The relationship between distance from the sun and orbital period is that as the distance from the sun increases, the orbital pe

riod increases.
We can see this because as we go through the planets in our solar system, the farther away they are from the Sun, the longer their orbital period becomes. For example, Mercury is about 67 million km away from the Sun and has an orbital period of 88 days, where as Neptune is about 4.5 billion km away from the Sun and has an orbital period of 165 years.

This tells us that as the distance from the sun increases, gravity _________________. Because gravity _______________, the orbital period is __________________.
Physics
1 answer:
iren [92.7K]2 years ago
4 0
Second law is it:))))))))
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Joe and Max shake hands and say goodbye. Joe walks east 0.40 km to a coffee shop, and Max flags a cab and rides north 3.65 km to
katen-ka-za [31]

Answer:

3.67 km

Explanation:

Joe distance towards coffee shop is,

OB=0.40 km

And the Max distance towards bookstore is,

OA=3.65 km

Now the distance between the Joy and Max will be,

By applying pythagorus theorem,

AB=\sqrt{OB^{2}+OA^{2}}

Substitute 0.40 km for OB and 3.65 km for OA in the above equation.

AB=\sqrt{0.40^{2}+3.65^{2}}\\AB=\sqrt{13.4825} \\AB=3.67 km

Therefore the distance between there destination is 3.67 km.

6 0
3 years ago
We have two solenoids: solenoid 2 has twice the diameter, half the length, and twice as many turns as solenoid 1. The current in
leva [86]

Answer:

the field at the center of solenoid 2 is 12 times the field at the center of solenoid 1.

Explanation:

Recall that the field inside a solenoid of length L, N turns, and a circulating current I, is given by the formula:

B=\mu_0\, \frac{N}{L} I

Then, if we assign the subindex "1" to the quantities that define the magnetic field (B_1) inside solenoid 1, we have:

B_1=\mu_0\, \frac{N_1}{L_1} I_1

notice that there is no dependence on the diameter of the solenoid for this formula.

Now, if we write a similar formula for solenoid 2, given that it has :

1) half the length of solenoid 1 . Then L_2=L_1/2

2) twice as many turns as solenoid 1. Then N_2=2\,N_1

3) three times the current of solenoid 1. Then I_2=3\,I_1

we obtain:

B_2=\mu_0\, \frac{N_2}{L_2} I_2\\B_2=\mu_0\, \frac{2\,N_1}{L_1/2} 3\,I_1\\B_2=\mu_0\, 12\,\frac{N_1}{L_1} I_1\\B_2=12\,B_1

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Hey there!

Option A

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steposvetlana [31]

Concentrated solar power facilities are solar power—generating facilities that generate electricity at large centralized facilities and transmit that power to homes and businesses through the electric grid .

<h3>What is solar power?</h3>

Solar power refer to electric power or electricity that is generated from sun rays or radiations while using solar panels and other technologies.

Therefore, Concentrated solar power facilities solar power—generating facilities that generate electricity at large centralized facilities and transmit that power to homes and businesses through the electric grid.

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Explanation:

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